Sweating is your body releasing water to cool it’s self down. When doing an activity the water in ur body warms up. And is then released to stop from overheating
The correct answer is - A) The major constituents of air are gaseous elements.
With the statement ''the major constituents of air are gaseous elements'' we can easily conclude that the air is a mixture. The reason for that is that we have a plural usage of the word element, elements, which mean that there are multiple elements that make up the air.
The air is indeed predominantly a mixture of gaseous elements. The most abundant gas in the air being the nitrogen with 78.9%, oxygen with 20.95%, argon 0.93%, and carbon dioxide 0.04%, with lesser amounts of other gases also be present in it. The water vapor is also present in the air, though it is variable, being around 1% at sea level, but only 0.4% over the entire atmosphere.
Answer:
306.6g/mol
Explanation:
To calculate molecular weight you need to know how many grams ou have in a determined amount of moles of substance. As you have the mass of the sample (1.42g), you need to find how many moles are, as follows:
The reaction of the acid HX with the base YOH is:
HX + YOH → H₂O + YX
<em>1 mole of acid reacts per mole of base.</em>
<em />
In a titration, the solution turned pink when moles base = moles acid.
Moles of base that the student added (Using the volume and molarity of the solution) are:
32.48mL = 0.03248L ₓ (0.1426 moles base / L) = 0.004632 moles of base
As the titration is in equivalence point, there are 0.004632 moles of the acid
Molecular weight (Ratio between grams of sample and its moles) is:
1.42g / 0.004632 moles =
<h3>306.6g/mol</h3>
Explanation:
As molarity is the number of moles placed in a liter of solution. Therefore, no. of mole = Molarity × volume of solution in liter
Hence, moles of 
will be calculated as follows.
No. of mole of = 
= 0.0168 mole
According to the given reaction, 2 mole of react with 4 mole of KI.
Therefore, for 0.0168 mole amount of required will be as follows.
= 
= 0.0337 mole of KI
Hence, volume of KI required will be calculated as follows.
Volume = 
Volume of KI = 
= 0.1614 liter
= 161.4 ml (as 1 L = 1000 mL)
Thus, we can conclude that 161.4 ml volume of a 0.2089 M KI is required for the given situation.
