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monitta
3 years ago
15

I need help plzz What is m 50* 35* 130* 95*

Mathematics
2 answers:
Dmitry [639]3 years ago
6 0

Answer:

The answer is 50, can I also get Brainliest?

blagie [28]3 years ago
5 0

Answer:

the answer is 50!

Step-by-step explanation:

The person above me is also correct mark him as brainliest

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WILL MARK BRAINLIEST!!! PLEASE ANSWER!!! WRONG ANSWERS JUST FOR POINTS WILL BE REPORTED!!!!!!!!!!!!!!
Alchen [17]

Answer:

where's the question???

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Solve for x9(x + 1) = 25 + x
vaieri [72.5K]
When you expand the equation, you will have
9x + 9=25 + x
Next you have to collect like terms
+x will go over the equality sign to become -x. The same applies to +9
9x - x=23 - 9
9x minus x is 8x
8x=14
Divide both sides by 8
x=14/8
You will have 1 6/8
6 is the remainder while 1 is the number of times 8 divided 14.
In decimal, it will be 1.75
Hope that helped. Good luck
8 0
3 years ago
Read 2 more answers
Find the area please
tatuchka [14]

Answer:

D

Step-by-step explanation:

Recall that the area of a triangle is given by:

\displaystyle A = \frac{1}{2} bh

In this case, the base is <em>x</em> and the height is <em>y</em>. Hence:

\displaystyle A = \frac{1}{2} xy

We can write the following ratios:

\displaystyle \sin \alpha = \frac{x}{12} \text{ and } \cos \alpha = \frac{y}{12}

Solve for <em>x</em> and <em>y</em>:

\displaystyle x = 12\sin \alpha \text{ and } y = 12\cos \alpha

Substitute:

\displaystyle A = \frac{1}{2}\left(12\sin \alpha\right)\left(12\cos \alpha\right)

And simplify. Hence:

\displaystyle A = 72\sin \alpha \cos\alpha

In conclusion, our answer is D.

6 0
2 years ago
Use the relationship between the sine and cosine functions to fill in each blank .
rjkz [21]

Answer:

sin(12°)

Step-by-step explanation:

Because sine and cosine are cofunctions, we can use the relation sin(90° - θ) = cosθ to show that cos(78°) = sin(90° - 78°) = sin(12°)

8 0
3 years ago
What is the answer to ax+z =aw-y if you are solving for a
inysia [295]
Ax + z = aw - y....subtract aw from both sides
ax - aw + z = -y....subtract z from both sides
ax - aw = -y - z....factor out a on the left side
a(x - w) = -y - z...divide both sides by (x-w)
a = (-y - z) / (x - w)
7 0
3 years ago
Read 2 more answers
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