Divide 3 on the numerator and denominator.
Hoped this helped.
~Bob Ross®
Answer:
a
The null hypothesis is ![H_o : p = 0.67](https://tex.z-dn.net/?f=H_o%20%20%3A%20%20p%20%3D%20%200.67)
The alternative hypothesis is ![H_a : p \ne 0.67](https://tex.z-dn.net/?f=H_a%20%3A%20p%20%5Cne%200.67)
b
The sample proportion is ![\^ p = 0.65](https://tex.z-dn.net/?f=%5C%5E%20p%20%20%3D%20%200.65)
Step-by-step explanation:
From the question we are told that
The sample size is n = 546
The number of people that use a laptop overnight is ![k = 355](https://tex.z-dn.net/?f=k%20%3D%20355)
The population proportion is ![p = \frac{2}{3} = 0.67](https://tex.z-dn.net/?f=p%20%3D%20%20%5Cfrac%7B2%7D%7B3%7D%20%20%3D%20%200.67)
Generally
The null hypothesis is ![H_o : p = 0.67](https://tex.z-dn.net/?f=H_o%20%20%3A%20%20p%20%3D%20%200.67)
The alternative hypothesis is ![H_a : p \ne 0.67](https://tex.z-dn.net/?f=H_a%20%3A%20p%20%5Cne%200.67)
Gnerally the sample proportion is mathematically represented as
![\^ p = \frac{ k}{n}](https://tex.z-dn.net/?f=%5C%5E%20p%20%20%3D%20%20%5Cfrac%7B%20k%7D%7Bn%7D)
=> ![\^ p = \frac{ 355}{546}](https://tex.z-dn.net/?f=%5C%5E%20p%20%20%3D%20%20%5Cfrac%7B%20355%7D%7B546%7D)
=> ![\^ p = 0.65](https://tex.z-dn.net/?f=%5C%5E%20p%20%20%3D%20%200.65)
Each pencil cost $2.
Explanation: She had $24 before buying the pencils and after she had $10. 24-10=14 so the total she spent on pencils was $14. She bought 7 pencils so you divide 14 by 7 (14/7=2) which equals 2. So each pencil cost $2.
Answer:
0.1 atoms
Step-by-step explanation:
Typically, there is 0.1 atoms in each cubic centimeter of interstellar wind, and 10 ions in each cubic centimeter of solar wind (versus surface air which contains 3 x 10^19 molecules per cc). This means there is a great deal of dead space between the very tiny particles and collisions are rare.
Answer:
D. 116
Step-by-step explanation:
![V=(\frac{1}{3})\pi r^{2}h](https://tex.z-dn.net/?f=V%3D%28%5Cfrac%7B1%7D%7B3%7D%29%5Cpi%20r%5E%7B2%7Dh)
V = (1/3)π(4)²(6.9)
V = 36.8π
V ≈ 115.55
<em>Note: You will NEVER use slant height to calculate the area, only to calculate the normal height if unknown. In this problem, we did not use it at all so try not to get confused!</em>
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<h2>BRAINLIEST please if this helped!</h2>