h = t - 15
h + t = 33
Because we have a value of h, we can plug it into the second equation to solve for t.
t - 15 + t = 33
Add 15 to both sides.
t + t = 48
Combine like terms.
2t = 48
Divide both sides by 2.
t = 24
<h3>Thomas's age is 24.</h3>
Divide 324 by 24. Which is 13.5
1. Given any triangle ABC with sides BC=a, AC=b and AB=c, the following are true :
i) the larger the angle, the larger the side in front of it, and the other way around as well. (Sine Law) Let a=20 in, then the largest angle is angle A.
ii) Given the measures of the sides of a triangle. Then the cosines of any of the angles can be found by the following formula:
a^{2}=b ^{2}+c ^{2}-2bc(cosA)
2.
20^{2}=9 ^{2}+13 ^{2}-2*9*13(cosA) 400=81+169-234(cosA) 150=-234(cosA) cosA=150/-234= -0.641
3. m(A) = Arccos(-0.641)≈130°,
4. Remark: We calculate Arccos with a scientific calculator or computer software unless it is one of the well known values, ex Arccos(0.5)=60°, Arccos(-0.5)=120° etc
That whole number is 277,349.
When we partition a number line from 0 to 1 into six, each segment has a length of 1/6 and the segments are:
1/6. 2/6. 3/6, 4/6, 5/6 , 6/6
Breaking 2/6 into 4 equal parts, we get each part equal to 1/12
