Answer:
The length of AA' = √29 = 5.39
Step-by-step explanation:
* Lets revise how to find the length of a line joining between
any two points in the coordinates system
- If point A is (x1 , y1) and point B is (x2 , y2)
- The length of AB segment √[(x2 - x1)² + (y2 - y1)²]
* Lets use this rule to solve the problem
∵ Point A is (0 , 0)
∵ Point A' = (5 , 2)
∵ (x2 - x1)² = (5 - 0)² = 5² = 25
∵ (y2 - y1)² = (2 - 0)² = 2² = 4
∴ The length of AA' = √(25 + 4) = √29 = 5.39
476.00×5%=23.80 tax=476+23.80=499.80
499.80×15%=74.97
499.80+74.97=574.77
Answer:
1/6
Step-by-step explanation:
The gradient of the line segment is the same as slope
m = (y2-y1)/(x2-x1)
= ( -4 - -5)/( 2 - -4)
= (-4+5)/( 2 +4)
1/6
Answer:
m= 2 / 3 b= -2
Step-by-step explanation:
you have to look at the graph to find the y-intercept
then do this to find the slope
m =
y2 - y1
x2 - x1
you plug in all the numbers to get
m=
<u>0+4</u>
3+3
(it would be 3 minus, negative 3 which looks like: 3- - 3 becomes 3+3)
m=
<u>4</u>
6
and simplified that would be
m= 2/3
