(4x³+ 13x − 7) − (6x²<span>+ 9x + 2)
Remember that if they don't have the same exponents/bases (x</span>²,x³, etc.), then they cannot be grouped together.
This means that 4x³ and 6x² will be left alone because there are no other x² or x³ in the expression.
So first thing you do is distribute. Don't forget about that - in front of the second parentheses.
(4x³+ 13x − 7) − (6x²+ 9x + 2)
(4x³ + 13x − 7) + (−6x² - 9x - 2)
4x³ - 6x² + (13x - 7) + (-9x - 2)
4x³ - 6x² + 4x (- 7) + (- 2)
4x³ - 6x² + 4x - 9
So the answer is:
C. <span>4x3− 6x2+ 4x − 9</span>
Answer:
A)

B)

C)

Step-by-step explanation:
We are given the function:

A)
Given that h(1) = 20, we want to find <em>k</em>.
h(1) = 20 means that <em>h</em>(x) = 20 when <em>x</em> = 1. Substitute:

Simplify:

Anything raised to zero (except for zero) is one. Therefore:

B)
Given that h(1) = 40, we want to find 2<em>k</em> + 1.
Likewise, this means that <em>h</em>(x) = 40 when <em>x</em> = 1. Substitute:

Simplify:

We can take the natural log of both sides:

By definition, ln(e) = 1. Hence:

Therefore:

C)
Given that h(1) = 10, we want to find <em>k</em> - 3.
Again, this meas that <em>h</em>(x) = 10 when <em>x</em> = 1. Substitute:

Simplfy:

Take the natural log of both sides:

Therefore:

Therefore:

Mode, because mode is the number that shows up most often.
Answer:
(3x+4)(3x+2)
Step-by-step explanation:
Answer:
arithmetic
Step-by-step explanation:
an arithmetic sequence is when you add or minus the same number