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Yuliya22 [10]
3 years ago
7

What is the general equation of a sine function with an amplitude of 6, a period of pi/4, and a horizontal shift of pi/2?

Mathematics
1 answer:
agasfer [191]3 years ago
4 0

The general equation of the sine function y=f(x) is defined as

Y=AsinB(x-C)+D

where A is the Amplitude

B represents the frequency of the function with period equals 2\pi/B

C represents the Horizontal shift, For Phase shift= -C/B

D represents the Vertical shift.

The data given that the amplitude of the function A=6

B=\frac{2\pi}{Current\,  period}=\frac{2\pi}{\pi/4}=8

Vertical shift D= 0

Horizontal Shift C= \pi/2

Now plug in \neq A=6, B=8\,  and \, C=\pi/2 in the general equation of sine function, we get

y=6\sin8(x-\pi/2)+0\\y=6\sin 8(x-\pi/2))

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