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3 years ago

I will give brainiest to the first person to tell me who is the Carolina panther QB

Physics

1 answer:

Inessa [10]3 years ago

7 0

Answer:

Cam Newton (currently but might change because he has been allowed to trade)

Will Grier

Kyle Allen

Explanation:

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should I tell penny, potato chip and used napkin that I've made new friends and moved on. I don't want to make them sad. :(

MrRa [10]

Answer: ok

Explanation:

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2 years ago

Read 2 more answers

Mendel wanted to find out if the pattern of inheritance for one trait affected the pattern of inheritance for anther. What exper

Inga [223]

Answer is given below :

Explanation:

He tested the seed color and shape. At the same time Gregor Mendel focused his search on seed size, flower color, seed coat color, pod size, immature pod color, flower position and pea plant height.
To describe the results he drew, he coined the terms 'recessive' and 'dominant'.

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3 years ago

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Which of the following is not a colligative property? a. osmotic pressure b. lattice energy c. vapor-pressure lowering d. boilin

Gre4nikov [31]

Answer:

b) lattice energy

Explanation:

A solution is said to have colligative property when the property depends on the solute present in the solution.

Colligative property depend upon on the solute particle or the ion concentration not on the identity of solute.

osmotic pressure, vapor pressure lowering , boiling point elevation and freezing point lowering all depend upon solute concentration so they will not have colligative property so, the answer remains option 'b' which is lattice energy.

8 0

3 years ago

A typical helium-neon laser found in supermarket checkout scanners emits 633-nm-wavelength light in a 1.0-mm-diameter beam with

Fofino [41]

Answer:

Eo = 9.796 x 10^2 N/C

Bo = 3.266 x 10^-6 T

Explanation:

Given

Wavelength λ = 633 nm

Diameter of the beam D = 1.0 mm

Power P = 1.0 mW

Solution

Radius of the beam r = D/2 = 0.5 mm = 0.0005 m

Area of cross section

$A = \pi r^{2} \\A = 3.15 \times 0.0005^{2}\\A = 7.58 \times 10^{-7} m^{2}\\$

Intensity

$I = \frac{P}{A} \\I = \frac{0.001}{7.85\times 10^{-7}} \\I = 1273.885 {W}/{m^{2} }$

Amplitude of Electric Field

$E_{o} = \sqrt{\frac{2I}{ \epsilon_{o}c } } \\E_{o} = \sqrt{\frac{2 \times 1273.88}{ 8.85 \times 10^{-12} \times 3 \times 10^{8} } }\\E_{o} = 9.796 \times 10^{2}N/C$

Amplitude of Magnetic Field

$B_{o} = \sqrt{\frac{2 \mu_{o}I}{c } } \\B_{o} = \sqrt{\frac{2 \times 4 \times \pi \times 10^{-7} \times 1273.88}{ 3 \times 10^{8} } }\\B_{o} = 3.266 \times 10^{-6} T$

5 0

3 years ago

A hollow, conducting sphere with an outer radius of 0.240 m and an inner radius of 0.200 m has a uniform surface charge density

GarryVolchara [31]

A. What is the new charge density

5 0

2 years ago