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hjlf
4 years ago
7

The picture above shows a football player kicking a football. This is known as two dimensional motion. In which direction does t

he football move?
A) vertical only (y)
B) horizontal only (x)
C) horizontal and vertical (x, y)
D) horizontal, vertical, and side to side (x, y, and z)

The diagram shows the motion of a tennis ball that has just been hit with a racket (air resistance is neglected). Which of these is true of the horizontal and vertical components of the ball’s velocity?
A) Both the horizontal and the vertical components are constant.
B) Both the horizontal and the vertical components are accelerated.
C) The horizontal component is constant but the vertical component is accelerated.
D) The horizontal component is accelerated but the vertical component is constant.

Physics
1 answer:
fgiga [73]4 years ago
8 0

1. C) horizontal and vertical (x, y)

The picture shows the motion of a projectile, which consists of two separate motions along two different directions:

- horizontal (x): along this direction, the football has a uniform motion, with constant horizontal speed v_0 cos \theta,where v_0 is the magnitude of the initial velocity of the ball and \theta the angle at which it has been thrown

- vertical (y): along this direction, the football has an accelerated motion, with initial vertical velocity v_0 sin \theta upward and constant acceleration g=9.8 m/s^2 downward (acceleration due to gravity)


2. C) The horizontal component is constant but the vertical component is accelerated.

As described in the previous part of the exercise:

- along the horizontal direction there are no forces exerted on the ball, so it is a uniform motion, therefore the acceleration is zero and the horizontal component of the velocity is constant

- along the vertical direction there is one force acting on the ball (the force of gravity, which pushes downward), so there is an acceleration (downward) equals to g=9.8 m/s^2 and therefore the vertical component of the velocity is not constant.

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The mass of a glass beaker is known to be 24.2 g. Approximately 5 mL of water are added, and the mass of the beaker and water is
Kamila [148]

Answer: 2 significant figures in 6.4

Explanation:

Significant figures : The figures in a number which express the value -the magnitude of a quantity to a specific degree of accuracy is known as significant digits.

Rules for significant figures:

Digits from 1 to 9 are always significant and have infinite number of significant figures.

All non-zero numbers are always significant. For example: 654, 6.54 and 65.4 all have three significant figures.

All zero’s between integers are always significant. For example: 5005, 5.005 and 50.05 all have four significant figures.

All zero’s preceding the first integers are never significant. For example: 0.0078 has two significant figures.

All zero’s after the decimal point are always significant. For example: 4.500, 45.00 and 450.0 all have four significant figures.

Mass of beaker = 24.2 g

Mass of beaker + mass of water = 30.625 g

Mass of water = 30.625 - Mass of beaker = 30.625 - 24.2 = 6.4g

The rule apply for the addition and subtraction is :

The answer would contain same number of decimal places as there are in the least precise number present.

Thus there are 2 significant figures in mass of water which is 6.4 grams.

7 0
3 years ago
How is lithium fluoride and lithium chloride similar?
Blababa [14]

Answer:

Although odorless, lithium fluoride has a bitter-saline taste. Its structure is analogous to that of sodium chloride, but it is much less soluble in water. It is mainly used as a component of molten salts.

Explanation:

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Which of the answer choices best describes the property of volume? the amount of space a substance's matter occupies the amount
vova2212 [387]

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Formula One racers speed up much more quickly than normal passenger vehicles, and they also can stop in a much shorter distance.
klasskru [66]

Answer:

The magnitude of the car's acceleration as it slows during braking is 36.81 m/s²

Explanation:

From the question, the given values are as follows:

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Using the equation of motion, v² = u² + 2as

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220a = -8100

a = -8100/220

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The value for acceleration is negative showing that car is decelerating to a stop. The magnitude of the car's acceleration as it slows during braking is therefore 36.81 m/s²

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Answer:

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Explanation:

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