When a 25000-kg fighter airplane lands on the deck of the aircraft carrier, the carrier sinks 0.23cm deeper into the water.
1 answer:
Answer:
10604 square meters
Explanation:
0.23 cm = 0.0023m
Assume the carrier has a shape of a rectangular box. When the carrier sinks 0.0023m deeper into water, the extra volume submerged into water is the same as the extra water volume being replaced. This extra volume would add an additional buoyant force to counter balance the extra weight created by the 25000 kg fighter.
With g being constant, the mass of the extra water displaced is the same as the mass of the fighter airplane . And mass of the water displaced is its volume V times its density
We assume the carrier has a shape of a rectangular box, so this extra displaced volume is the extra depth d = 0.0023 m times cross-section area A
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6.5454 m
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Answer:
a
The hiker (you ) is 200 m below his/her(your) starting point
b
The resultant displacement in the north east direction is
The resultant displacement in vertical direction (i.e the altitude change )
Explanation:
From the question we are told that
The displacement in the morning is
The displacement in the afternoon is
Generally the direction west is negative , the direction east is positive
the direction south is negative , the direction north is positive
resultant displacement is mathematically evaluated as
From the above calculation we see that at the end of the hiking the hiker (you) is 200 m below his/her(your) initial position
Generally from Pythagoras theorem , the resultant displacement in the north east direction is
=>
Generally from Pythagoras theorem , the resultant displacement in vertical direction (i.e the altitude change )
=>