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Alekssandra [29.7K]
4 years ago
5

When a 25000-kg fighter airplane lands on the deck of the aircraft carrier, the carrier sinks 0.23cm deeper into the water.

Physics
1 answer:
Genrish500 [490]4 years ago
4 0

Answer:

10604 square meters

Explanation:

0.23 cm = 0.0023m

Assume the carrier has a shape of a rectangular box. When the carrier sinks 0.0023m deeper into water, the extra volume submerged into water is the same as the extra water volume being replaced. This extra volume would add an additional buoyant force to counter balance the extra weight created by the 25000 kg fighter.

With g being constant, the mass of the extra water displaced is the same as the mass of the fighter airplane m_f. And mass of the water displaced is its volume V times its density \rho

V\rho = m_f

1025V = 25000

V = 25000/1025 = 24.39 m^3

We assume the carrier has a shape of a rectangular box, so this extra displaced volume is the extra depth d = 0.0023 m times cross-section area A

V = dA

24.39 = 0.0023A

A = 24.39 / 0.0023 = 10604 m^2

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Answer:

(a) Force must be grater than 283.87 N

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Explanation:

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Coefficient of kinetic friction \mu _k=0.399

(a) Static friction force is given by F_S=\mu _smg=0.584\times 49.6\times 9.8=283.8707N

So to just start the crate moving we have to apply more force than 283.87 N

(B) This force will be equal to kinetic friction force

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What is the relationship between mass and weight in physics?
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2 years ago
A platinum ball weighing 100 g is removed from a furnace and dropped into 400 g of water at 0 degree C. If the equilibrium tempe
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Answer:

T = 1010 degree Celsius

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we can calculate the temperature of the furnace from the equation before

Mb x C x (temp of furnace (T) - equilibrium temp) = Mw x (equilibrium temp - temp of furnace)

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Answer:

* The first thing we observe is that the frequency response does not change

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