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3 years ago

Can someone please help me

Physics

1 answer:

VikaD [51]3 years ago

4 0

Answer:

I don't know the answer but I needed the answer to that on a quiz and I downloaded sorcatic and it brings u to an app or website with the answer I hope this helps if you can't find the app than just tell me

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Смоктати півень мій друг

kaheart [24]

What uhhhhhhhhhhhhhhhhhhhhh

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3 years ago

Which statement is true about the technology used to improve the motion of space vehicles on rough surfaces?

Andrei [34K]

The correct answer is C.)

It has made road vehicles safer because magnetometers are used to detect particles found in radiation emitted during combustion of fuel.

h a v e a g r e a t d a y

4 0

3 years ago

What is the resultant of a pair of one pound forces at right angles to each other?

OleMash [197]

Answer:

$F_R=\sqrt{2} \ pound.force$

Explanation:

Given that there are two force of 1 pound each at right angles to each other.

The from the vector law of addition:

$F_R=\sqrt{F_1^2+F_2^2}$

where:

$F_R=$ resultant force

$F_1\ \&\ F_2$ be the two of the forces to be added.

$F_R=\sqrt{1^2+1^2}$

$F_R=\sqrt{2} \ pound.force$

8 0

4 years ago

Assume that the operating cost of a certain truck (excluding driver's wages) is 12+x/6 cents per mile when the truck travels at

podryga [215]

Answer:

$x = 60 mph$

Explanation:

Given that the operating cost is

$c = 12 + \frac{x}{6}$ cents per mile

total miles covered is given as

$d = 400 miles$

so total cost of drive is given as

$C = (12 + \frac{x}{6})(4)$ $

time taken by the truck to move the distance is given as

$t = \frac{400}{x}$

So total earnings of the driver is given as

$E = \frac{400}{x} \times 6$ $

now total profit of the driver is given as

$P = \frac{2400}{x} - (48 + \frac{2x}{3})$ $

to maximize the profit we have

$\frac{dP}{dx} = 0$

$-\frac{2400}{x^2} + \frac{2}{3} = 0$

so we have

$x = 60 mph$

8 0

3 years ago

(II) A 1200-kg car moving on a horizontal surface has speed v = 85 km/h when it strikes a horizontal coiled spring and is brough

Pie

Answer:

k = 138440 N/m

Explanation:

given,

Mass of the car = 1200 Kg

speed of the car = 85 km/h

= 85 x 0.278 = 23.63 m/s

KE of the car

$KE = \dfrac{1}{2} mv^2$

Using Spring Energy Formula

$KE_{spring}=\dfrac{1}{2}kx^2$

Using conservation of energy

$\dfrac{1}{2} mv^2=\dfrac{1}{2}kx^2$

$k = \dfrac{mv^2}{x^2}$

$k = \dfrac{1200\times 23.63^2}{2.2^2}$

k = 138440 N/m

Spring stiffness constant of the spring is equal to k = 138440 N/m

7 0

3 years ago