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yKpoI14uk [10]
3 years ago
7

Explain on a particle basis how the addition of a solute affects the boiling point, the freezing point, and the vapor pressure o

f the solvent.
Chemistry
1 answer:
Tems11 [23]3 years ago
6 0
A solute adds particles to a solution, such as:

NaCl-> Na+ + Cl- This puts 2 particles in the solution for every 1 formula unit of table salt. Any particle that gets added to a liquid interferes with the liquids ability to form crystals (ice), it interferes with the liquids ability to break surface tension ( boiling), and since less liquid molecules can escape there is less vapor pressure.

Addition of a solute means:

To freeze the solution you would have to slow the molecules down more than normal to encourage crystal growth, so the temp must be lowered.

To boil the solution you would have to speed the molecules up more than normal to encourage the molecules to leave the liquid, so the temp must be increased.

To increase the vapor pressure of the solvent has the same explanation as boiling.
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The pale yellow liquid bromine pentafluoride reacts violently with water to give a mixture of bromic acid and hydrofluoric acid
topjm [15]

Answer:

The concentration of bromic acid (HBrO₃) is 0.069 moles/L

the concentration of hydrofluoric acid (HF) is 0.345 moles/L

Explanation:

(a) The balanced chemical equation for the reaction is

BrF₅ + 3H₂O → HBrO₃ + 5HF

The chemical equation is balanced

(b) To determine the concentration of each acids,

First, we will determine the different volume of the acids yielded

The solution volume is 783 mL = 0.783 L

From the balanced chemical equation,

1 mole of BrF₅ produces 1 mole of HBrO₃

Likewise, 1 mole of BrF₅ will produce 5 moles of HF

From the question,

5.40×10⁻² moles of bromine pentafluoride (BrF₅) reacted;

Hence, 5.40×10⁻² moles of HBrO₃ will be produced

and 5 × 5.40×10⁻² moles of HF will be produced.

Number of moles of HBrO₃ produced = 5.40×10⁻² moles

and Number of moles of HF produced = 2.7 × 10⁻¹ moles

From the formula,

Number of moles (n) = Concentration (C) × Volume (V)

Then,

Concentration (C) = Number of moles (n) / Volume (V)

For bromic acid (HBrO₃)

n = 5.40×10⁻² moles

Volume = 0.783L

Hence,

C = 5.40×10⁻² moles / 0.783L

C = 0.069 moles/L

This is the concentration of bromic acid (HBrO₃)

For hydrofluoric acid (HF)

n = 2.7 × 10⁻¹ moles

V = 0.783L

Hence,

C = 2.7 × 10⁻¹ moles / 0.783L

C = 0.345 moles/L

This is the concentration of hydrofluoric acid (HF)

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3 years ago
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