Answer: The volume of a 0.10 mol/l HCl solution needed to neutralize 10 ml of a 0.15 mol/l LiOH solution is 15 ml
Explanation:
To calculate the volume of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is 
are the n-factor, molarity and volume of base which is LiOH.
We are given:
Putting values in above equation, we get:
Thus the volume of a 0.10 mol/l HCl solution needed to neutralize 10 ml of a 0.15 mol/l LiOH solution is 15 ml
Answer:
8 electrons
Explanation:
Phosphorous is the element of group 15 and third period. The atomic number of chlorine is 15 and the symbol of the element is P.
The electronic configuration of the element phosphorus is:-
Thus, from the electronic configuration shown above,
In n = 2, the total number of electrons are 8 which are present in 
Answer is: 0.330 ppm
Hope this helps
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