C
The forward and reverse processes would still be ongoing (the system is not still as in the case of static equilibrium), however, the net effect between the two processes is zero. This is what is referred to as dynamic equilibrium.
A closed system, is one that does not exchange matter or energy between it and the environment.
Explanation:
Take an example of a simplest reversible reaction like the following;
A ⇔ B
To get the dynamic equilibrium constant for the reaction we use the following equation;
Keq = [B]eq / [A]eq
Where eq denotes equilibrium.
An example of a reversible reaction where this applies is;
NH₄Cl (s) ⇔ NH₃ (g) + HCl (g)
Learn More:
For more on thermodynamic equilibrium check out;
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Jot down the formula of the ionic compound. Let's say the ionic compound you're working with is NaCl. ...
Write the name of the metal. ...
Add the name of the non-metal with an –ide ending. ...
Combine the cation and anion names. ...
Practice naming more simple ionic compounds.
<u><em>Please mark as brainliest</em></u>
Answer:
pure substance
Explanation:
A pure substance is a form of matter that has a constant composition (meaning it's the same everywhere) and properties that are constant throughout the sample (meaning there is only one set of properties such as melting point, color, boiling point, etc. throughout the matter).Ja
Answer:
Molecular oxygen and Hydrogen fluoride.
Explanation:
Definition:
Hydrogen bonding:
It is a type of dipole-dipole attraction between the hydrogen atom and more electronegative atoms.
In hydrogen bonding mostly the highly electronegative atoms are fluorine, nitrogen and oxygen.
Explanation:
In given compound such as methane CH₄ the electronegativity of carbon is 2.55 while that of hydrogen is 2.2 so there is smaller electronegativity difference that's why it can not form hydrogen bond.
In case of molecular oxygen the electronegativite atom oxygen is present. It can form hydrogen bonds with water. its electronegativity is 3.44.
In case of hydrogen fluoride the electronegativity atom fluorine is present. It will form hydrogen bonds with water. Its electronegativity is 3.98. So it is more likely to take part in hydrogen bonding.
Answer:
(a) Alkali metals: Francium (Fr)
(b) Chalcogens: Polonium (Po)
(c) Noble gases: Radon (Rn)
(d) Alkaline earth metals: Radium (Ra)
Explanation:
In the periodic table, the atomic mass increases down the group. Therefore, the last element of a group is the heaviest element of the group.
(a) alkali metals: The chemical elements that are present in group 1 of the periodic table, except hydrogen.
<u>The heaviest member of this group is francium (Fr)</u>
(b) chalcogens: The chemical elements that are present in group 16 of the periodic table
<u>The heaviest member of this group is polonium (Po)</u>
(c) noble gases: The chemical elements that are present in group 18 of the periodic table
<u>The heaviest member of this group is radon (Rn)</u>
(d) alkaline earth metals: The chemical elements that are present in group 2 of the periodic table.
<u>The heaviest member of this group is radium (Ra)</u>