1,000 grams = 1 kilogram
2,000 grams = 2 kilograms
3,000 grams = 3 kilograms
4,000 grams = 4 kilograms
5,000 grams = 5 kilograms
.
.
10,000 grams = 10 kilograms
.
.
20,000 grams = 20 kilograms
.
.
30,000 grams = 30 kilograms
<span>(a) 5(3m+2) = 15m + 10
(b) 6(g+h) = 6g + 6h
(c) 4d+8 = 4(d + 2)
(d) 21p+35q = 7(3p + 5q)
(e) 18x+9y = 9(2x + y)</span>
Answer:
<h3>
a = (2mz - 3m)/4</h3>
Step-by-step explanation:
2z = 4a/m +3
-3 -3
2z - 3 = 4a/m
×m ×m
(2z -3)m = 4a
÷4 ÷4
[(2z -3)m]/4 = a
a = (2mz - 3m)/4
Answer:
166.32
Step-by-step explanation:
brainliest please
Answer:
x° = ∠OBR = ∠ABC (base angles of a cyclic isosceles trapezoid)
Step-by-step explanation:
APRB form a cyclic trapezoid
∠APO = x° (Base angle of an isosceles triangle)
∠OPR = ∠ORP (Base angle of an isosceles triangle)
∠ORB = ∠OBR (Base angle of an isosceles triangle)
∠APO + ∠OPR + ∠OBR = 180° (Sum of opposite angles in a cyclic quadrilateral)
Similarly;
∠ORB + ∠ORP + x° = 180°
Since ∠APO = x° ∠ORB = ∠OBR and ∠OPR = ∠ORP we put
We also have;
∠OPR = ∠AOP = ∠BOR (Alternate interior angles of parallel lines)
Hence 2·x° + ∠AOP = 180° (Sum of angles in a triangle) = 2·∠OBR + ∠BOR
Therefore, 2·x° = 2·∠OBR, x° = ∠OBR = ∠ABC.
