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natulia [17]
3 years ago
5

Hope this help good luck

Biology
1 answer:
Oksanka [162]3 years ago
6 0

ThE AnSweR is c. you has got it right yay

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in pea plants round seeds are dominant and wrinkled seeds are recessive. the cross rr x rr, what percentage of the offspring wil
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Answer:

0%

Explanation:

Round = Dominant

Wrinkled = recessive

Recessive = r

Dominant = R

homozygous dominant = RR

homozygous recessive = rr

Heterozygous= Rr

Since both seeds are homozygous recessive (rr)

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r r

r

r

Something like that.

Go across your four boxes and you will end up with;

rr, rr

rr, rr

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7 0
1 year ago
Where is the Straight of Hormuz?
OLEGan [10]

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6 0
3 years ago
o what temperature in oC must a 0.500 mole sample of O2 gas be adjusted in order to achieve a pressure of 4.00 atm in a 4.25 L c
Nesterboy [21]

Answer:

141C

Explanation:

We need to use the ideal gas law to solve this question. Ideal gas law: PV = nRT

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V = volume = 4.25L

n = number of moles = 0.500

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PV/nR = T

Now we can substitute the values.

(405.3 × 4.25) ÷ (0.500 × 8.314) = 414.3673322107 (answer in kelvin)

Convert 414.3673322107 Kelvin to Celsius.

0C = 273.15K (found on chemistry data sheet)

414.3673322107 - 273.15 = 141.2173322107C

141.2173322107 to nearest C = 141C

5 0
2 years ago
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