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statuscvo [17]
2 years ago
5

Find four numbers proportional to the numbers 2, 4, 5, and 6 if the difference between the sum of the two last numbers and the s

um of the first two numbers is equal to 4.8.
Mathematics
2 answers:
Nat2105 [25]2 years ago
7 0
Number 1 wants you to set up proportions so four numbers equal to 2/1 would be: 6/3 8/4 10/5 12/6, and so on. I'm not sure what they're asking when they say the sum of the first two numbers is equal to 4.8
mylen [45]2 years ago
3 0

Answer:

The numbers are 1.92 , 3.84 , 4.80 , and 5.76 .

Step-by-step explanation:

Let the numbers be represented by 2x, 4x, 5x, and 6x. Then the given condition says

(6x+5x)-(4x+2x) = 4.8

11x-6x=4.8

5x=4.8

x=.96

Then the numbers are

2x = 1.92

4x = 3.84

5x = 4.80

6x = 5.76

Hope this helps!

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Question 16 (Essay Worth 7 points)<br><br> Verify the identity.<br><br> tan (x + π/2) = -cot x
Rus_ich [418]

Step-by-step explanation:

We know that tan=sin/cos, so tan(x+π/2)=

\frac{sin(x+pi/2)}{cos(x+pi/2)}

Then, we know that sin(u+v)=sin(u)cos(v)+cos(u)sin(v),

so our equation is then

\frac{sin(x)cos(\pi/2)+cos(x)sin(\pi/2)}{cos(x+\pi/2)}  = \frac{cos(x)}{cos(x+\pi/2) }

Then, cos(u+v)=cos(u)cos(v)-sin(u)sin(v), so our expression is then

\frac{cos(x)}{cos(x)cos(\pi/2)-sin(x)sin(\pi/2)} = \frac{cos(x)}{-sin(x)} = -cot(x)

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Step-by-step explanation:


6 0
3 years ago
50 points and brainliest!!!!! fast pls!! (08.02)A pair of equations is shown below. x + y = 5 y = 1/2 x + 2 If the two equations
likoan [24]
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5 0
3 years ago
An article presents voltage measurements for a sample of 66 industrial networks in Estonia. Assume the rated voltage for these n
kramer

Answer:

We accept the null hypothesis and conclude that voltage for these networks is 232 V.

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 232 V

Sample mean, \bar{x} = 231.5 V

Sample size, n = 66

Sample standard deviation, s = 2.19 V

Alpha, α = 0.05

First, we design the null and the alternate hypothesis

H_{0}: \mu = 232\\H_A: \mu \neq 232

We use Two-tailed t test to perform this hypothesis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n-1}} } Putting all the values, we have

t_{stat} = \displaystyle\frac{231.5- 232}{\frac{2.19}{\sqrt{66}} } = -1.8548

Now,

t_{critical} \text{ at 0.05 level of significance, 9 degree of freedom } = \pm 1.9971

Since,              

|t_{stat}| > |t_{critical}|

We accept the null hypothesis and conclude that voltage for these networks is 232 V.

4 0
3 years ago
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