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2 years ago

PLEASE HELP URGENT!!

Mathematics

1 answer:

kodGreya [7K]2 years ago

7 0

Answer:

$26\:\mathrm{in^2}$

Step-by-step explanation:

The irregular polygon is made of a large rectangle with two smaller rectangles cut out of it. Therefore, we can find the area of the large rectangle and subtract these two smaller rectangles:

$10\cdot 5-2\cdot3\cdot4=50-24=\fbox{$26\:\mathrm{in^2}$}$ .

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The interior ages of a triangle have measure

Nina [5.8K]

Answer:

See below in bold.

Step-by-step explanation:

1. The 3 angles in a triangle add up to 180 degrees.

So x = 180 - (55 + 25)

= 180 - 80

= 100 degrees.

2. The 4 angles in a quadrilateral add up to 360 degrees,, so

3x + 127 + 54 + 119 = 360

3x + 300 = 360

3x = 360 - 300

3x = 60

x = 20 degrees.

3. Exterior angle

= 94 + 42

= 136 degrees.

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3 years ago

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Can anyone help me with this? is equations of lines.

vladimir2022 [97]

Answer:

x=16

Step-by-step explanation:

y = 1/2 x -3

Let y =5

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3 years ago

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Perform the indicated operation. (36m 2 - 60m + 25) ÷ (6m - 5)

9966 [12]

The correct answer for this is 6m - 5
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3 years ago

As part of a survey, 150 students were asked to name their favorite class. 50 points

disa [49]

A:40%
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2 years ago

businessText message users receive or send an average of 62.7 text messages per day. How many text messages does a text message

KiRa [710]

Answer:

(a) The probability that a text message user receives or sends three messages per hour is 0.2180.

(b) The probability that a text message user receives or sends more than three messages per hour is 0.2667.

Step-by-step explanation:

Let X = number of text messages receive or send in an hour.

The random variable X follows a Poisson distribution with parameter λ.

It is provided that users receive or send 62.7 text messages in 24 hours.

Then the average number of text messages received or sent in an hour is: $\lambda=\frac{62.7}{24}= 2.6125$ .

The probability of a random variable can be computed using the formula:

$P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!} ;\ x=0, 1, 2, 3, ...$

(a)

Compute the probability that a text message user receives or sends three messages per hour as follows:

$P(X=3)=\frac{e^{-2.6125}(2.6125)^{3}}{3!} =0.21798\approx0.2180$

Thus, the probability that a text message user receives or sends three messages per hour is 0.2180.

(b)

Compute the probability that a text message user receives or sends more than three messages per hour as follows:

P (X > 3) = 1 - P (X ≤ 3)

= 1 - P (X = 0) - P (X = 1) - P (X = 2) - P (X = 3)

$=1-\frac{e^{-2.6125}(2.6125)^{0}}{0!}-\frac{e^{-2.6125}(2.6125)^{1}}{1!}-\frac{e^{-2.6125}(2.6125)^{2}}{2!}-\frac{e^{-2.6125}(2.6125)^{3}}{3!}\\=1-0.0734-0.1916-0.2503-0.2180\\=0.2667$

Thus, the probability that a text message user receives or sends more than three messages per hour is 0.2667.

6 0

3 years ago