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stiks02 [169]
3 years ago
5

Help umm how do i do this im dumb idk how to do it :(

Mathematics
1 answer:
liq [111]3 years ago
3 0

Answer:

WITH DECIMAL: the bigger the demominateor (the bottom number) is, the smaller the value of the number. for ex. 1/4 is smaller then 1/2, 1/8 is bigger then 1/16, etc.

1/4 would go in between 0 and -1 because 1/4 isn't a whole number

-3 1/4 would go in between -3 and -4 becauce 3 AND 1/2 is more then just a 3

-2 3/4 would go in between -2 and -3 becasue 2 + other 3/4 is going to be bigger than 2 but smaller than a 3

9/4 is a tricky one casue 9 is bigger then 4. so you need to see how many times 4 goes into 9 (2 times = 4 +4 = 8) so the simplfied version would be 2 1/4 casue 9 - 8 = 1. so the 9/4 would go in between 2 and 3

lastly, the 3/4 would go in between 0 and 1 becasue 3/4 is deffinately smaller than 1 and definatly bigger than 0

(brainly are greatly appershated, commnet for help!)

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The board of a large company is made up of 7 women and 9 men. 6 of them will go as a delegation to a national conference.
Burka [1]

Answer:

a) 5765760

b) 60480

c) 5705280

Step-by-step explanation:

Assuming that order is not important:

Number of women = 7

Number of men = 9

Members of the delegation = 6

a) How many delegations are possible?

n=\frac{16!}{(16-6)!}=16*15*14*13*12*11\\ n= 5765760

b) How many of these delegations have all men?

n_{men} = \frac{9!}{(9-6)!}=9*8*7*6*5*4  \\n_{men} = 60480

c) How many of these delegations have at least one woman?

n_{women >0}=n-n_{men}\\n_{women >0} =5765760-60480\\n_{women >0} =5705280

4 0
3 years ago
What is the second step when factoring the trinomial
Burka [1]

<u>Answer</u>

Factor out the common factor.

<u>Explanation </u>

Factorization consists looking and writing numbers as a product other number. It is expressing number as a product of other numbers.

The first step involves looking for numbers factors and the second one is factoring the common factors.

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Step-by-step explanation:

They are the same; if you look at the figure, you can see that A and C are the same distance from each other and a ray in either direction would be equivalent to its counterpart.

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