<h3><u>Answers in Step-By-Step</u></h3>
Step-by-step explanation:
A; the admission price is $15
For adults its 2x
For students its x
and for children under 3 years old its 1/2x
to find the weekend money replace "x" with 15 as the money.
Adults: 2 * 15
students: 15
infants: 1/2 * 15
Do the math
2 * 15 = 30
15 = 15
1/2 * 15 = 7.5
B; A group of 4 adults, 5 students, and 2 children under the age of 3 visits the theme park on Sunday.
for each adult is $30
each student is $15
and children under 3 is $7.50
Do the math
30 * 4 = 120
15 * 5 = 75
2 * 7.5 = 15
120 + 75 + 15 = $210
C; If a student's weekday cost's $18, find the total admission cost that group B) has to pay.
Adult: 18 * 2
Student: 18
infant: 1/2 * 18
do the math
18 * 2 = 36
18 = 18
1/2 * 18 = 9
each adult is $36
each Student is $18
each infant is $9
4 adults, 5 students, 2 children under 3
4 * 36 = 144
5 * 18 = 90
9 * 2 = 18
144 + 90 + 18 = 252
The total would come out to $252
Since 425 is negative, it is far bellow zero. 212 is above zero. This means -425 is LESS THAN 212. So the answer would be A) -425°F<212°F
Answer:
3
Step-by-step explanation:
I used the MDAS method
ab^2x
\<span>ab^2x/ab^2y = --------------- = x/y. the ab^2 factor cancels from numerator
ab^2y and denominator.
</span>
Answer:
225 ft^2
Step-by-step explanation:
From what we have in the question, we have 60 ft of fencing
To maximize the area, we will need to have a square
For a square, the length of all sides are equal
Let us call one of the sides s
Thus, from the perimeter of the square;
4s = 60
s = 60/4
s = 15 ft
The area is thus, the product of the side length of the square
15 * 15 = 225 ft^2
