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Fudgin [204]
3 years ago
10

There are 24 girls on the track team. First race2/3 girl ran.only1/4 girl ran in second race. 1/6 on third race. Hiw many more g

irl ran in the first race than second
Mathematics
1 answer:
alukav5142 [94]3 years ago
5 0

Answer:

10 more girls

Step-by-step explanation:

So here 2/3 of 24 ran for first race

Then it gives us that 16 girls ran for first race.

Next, 1/4 of 24 ran for second race

That is 6 girls

The remaining girls ran for the third race,

24 - 22

2 girls

16 - 6 = 10

So for first race 10 more girls ran

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Answer:

The statement "500 divided by 50 is 10" is a true statement

Step-by-step explanation:

In mathematics, we have a term that we refer to as Place Value.

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500 ÷ 50 gives us 10.

This is true because, 500 as a number, the Digit 5 has a place value of hundreds

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10 as a number, the digit 1 has a place value of Tens.

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7 0
3 years ago
Given the preimage and image,find the dilation scale factor.​
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Answer:

The dilation scale factor is \frac{1}{2}.

Step-by-step explanation:

The image is the dilated form of its preimage if and only if the following conditions are observed:

1) K' = \alpha_{1} \cdot K

2) T' = \alpha_{2} \cdot T

3) P' = \alpha_{3} \cdot P

4) J' = \alpha_{4} \cdot J

5) \alpha_{1} = \alpha_{2} = \alpha_{3} = \alpha_{4}

If we know that K = (2, 0), K' = (1, 0), T = (3, 0), T' = (1.5,0), P = (1, 5), P' = (0.5, 2.5), J = (0, 3) and J' = (0, 1.5), then the coefficients are, respectively:

\alpha_{1} = \frac{1}{2}, \alpha_{2} = \frac{1}{2}, \alpha_{3} = \frac{1}{2}, \alpha_{4} = \frac{1}{2}

As \alpha_{1} = \alpha_{2} = \alpha_{3} = \alpha_{4}, we conclude that the dilation scale factor applied in the preimage is equal to \frac{1}{2}.

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