Steps:
1) determine the domain
2) determine the extreme limits of the function
3) determine critical points (where the derivative is zero)
4) determine the intercepts with the axis
5) do a table
6) put the data on a system of coordinates
7) graph: join the points with the best smooth curve
Solution:
1) domain
The logarithmic function is defined for positive real numbers, then you need to state x - 3 > 0
=> x > 3 <-------- domain
2) extreme limits of the function
Limit log (x - 3) when x → ∞ = ∞
Limit log (x - 3) when x → 3+ = - ∞ => the line x = 3 is a vertical asymptote
3) critical points
dy / dx = 0 => 1 / x - 3 which is never true, so there are not critical points (not relative maxima or minima)
4) determine the intercepts with the axis
x-intercept: y = 0 => log (x - 3) = 0 => x - 3 = 1 => x = 4
y-intercept: The function never intercepts the y-axis because x cannot not be 0.
5) do a table
x y = log (x - 3)
limit x → 3+ - ∞
3.000000001 log (3.000000001 -3) = -9
3.0001 log (3.0001 - 3) = - 4
3.1 log (3.1 - 3) = - 1
4 log (4 - 3) = 0
13 log (13 - 3) = 1
103 log (103 - 3) = 10
lim x → ∞ ∞
Now, with all that information you can graph the function: put the data on the coordinate system and join the points with a smooth curve.
<h2>
Hello!</h2>
The answer is: 
<h2>
Why?</h2>
Domain and range of trigonometric functions are already calculated, so let's discard one by one in order to find the correct answer.
The range is where the function can exist in the vertical axis when we assign values to the variable.
First:
: Incorrect, it does include 0.4 since the cosine range goes from -1 to 1 (-1 ≤ y ≤ 1)
Second:
: Incorrect, it also does include 0.4 since the cotangent range goes from is all the real numbers.
Third:
: Correct, the cosecant function is all the real numbers without the numbers included between -1 and 1 (y≤-1 or y≥1).
Fourth:
: Incorrect, the sine function range is equal to the cosine function range (-1 ≤ y ≤ 1).
I attached a pic of the csc function graphic where you can verify the answer!
Have a nice day!
1 and 2 are the factors its a compatable number
Forth degree trinomial because we have a number that’s to the exponent of four and we have 3 terms.
