I'm stuck on this question. Help please.
1 answer:
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For this case we have that the generic equation of the line is given by:
Where,
m: slope of the line
b: intersection with the y axis.
Since the line is parallel to PQ, then the slopes are equal.
We have then:
On the other hand we have:
Substituting values we have:
Answer:
The equation of the line that is parallel to line PQ and that has the and intercept b = -3 is:
Where,
m: slope of the line
b: intersection with the y axis.
Since the line is parallel to PQ, then the slopes are equal.
We have then:
On the other hand we have:
Substituting values we have:
Answer:
The equation of the line that is parallel to line PQ and that has the and intercept b = -3 is:
Answer:
(x - 6)² + (y - 7)² = 4
Step-by-step explanation:
Equation of circle: (x - h)² + (y - k)² = r²
Given center(h,k) = (6,7)
h = 6
k = 7
Dimeter = 4 --
radius, r = = 2
(x - h)² + (y - k)² = r²
(x - 6)² + (y - 7)² = 2²
(x - 6)² + (y - 7)² = 4