Answer:
For 1 mole of Lead(II)chlorie we have 1 mole of lead (Pb), 2 moles of Chlorine (Cl) and 4 moles of oxygen (O).
Explanation:
<u>Step 1: </u>Data given
Number of moles of Pb(ClO2)2 = 1
Since the oxidation number of Pb is 2+ and the oxidation number of ClO2 is -1
So to bind we should have <u>twice</u> ClO2
1 mole of Pb(ClO2)2 contains 1 mole of Pb; 1*<u>2</u>= 2 moles of Cl and 2*<u>2</u> = 4 moles of 0.
This means for 1 mole of Lead(II)chlorie we have 1 mole of lead (Pb), 2 moles of Chlorine (Cl) and 4 moles of oxygen (O).