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3 years ago

Exactly 1 mol Pb(ClO2)2 contains how many moles of Pb , Cl , and O ?

Chemistry

1 answer:

Masja [62]3 years ago

7 0

Answer:

For 1 mole of Lead(II)chlorie we have 1 mole of lead (Pb), 2 moles of Chlorine (Cl) and 4 moles of oxygen (O).

Explanation:

Step 1: Data given

Number of moles of Pb(ClO2)2 = 1

Since the oxidation number of Pb is 2+ and the oxidation number of ClO2 is -1

So to bind we should have twice ClO2

1 mole of Pb(ClO2)2 contains 1 mole of Pb; 1*2= 2 moles of Cl and 2*2 = 4 moles of 0.

This means for 1 mole of Lead(II)chlorie we have 1 mole of lead (Pb), 2 moles of Chlorine (Cl) and 4 moles of oxygen (O).

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The overall cell reaction occurring in an alkaline battery isZn(s) + MnO₂(s) + H₂O(l) → ZnO(s) + Mn(OH)₂(s) (e) In practice, vol

zubka84 [21]

b) Mass of MnO₂ = 5.981 g

Mass of H₂O = 1.2384 g

c) Total Mass of Reactant consumed = 11.708 g

b) Given Reaction

Zn(s) + MnO₂(s) + H₂O(l) → ZnO(s) + Mn(OH)₂(s)

Mass of Zn = 4.50 g

Moles of Zn = 0.0688 moles

Now,

Moles of Zn = moles of MnO₂ = moles of H₂O = moles of ZnO = moles of Mn(OH)₂

Hence ,

Moles of MnO₂ = 0.0688 moles

Mass of MnO₂ = 0.0688 × 86.9368 g

= 5.981 g

Similarly,

Moles of H₂O = 0.0688 moles

Mass of H₂O = 0.0688 × 18 g

= 1.2384 g

c) now ,

Moles of ZnO = 0.0688 moles

Mass of ZnO = 0.06880× 81.3794 g

= 5.598 g

Moles of Mn(OH)₂ = 0.0688 moles

Mass of Mn(OH)₂ =0.0688 × 88.952 g

= 6.11 g

Total mass of Product = 11.708 g

Total Mass of Reactant = 11.715 g

Hence,

Total mass of reactant consumed = 11.708 g

c) As total mass of reactant is more than that of mass of reactant consumed , Hence G is more than that of mass of reactant consumed .

G = - nFEcell

and no. of moles of reactant is greater than that of number of moles of reactant consumed .

Hence voltaic cell of given Capacity are heavier than that of mass of reactant consumed .

Thus from above conclusion we can say that , Mass of the reactant consumed is 11.708 g.

Learn more about Galvanic Cell here : brainly.com/question/19340007

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3 0

2 years ago

ICI has a higher boiling point then Br. What is the best explanation for this?

Ahat [919]

Br2 experiences dipole-dipole interactions. ICl experiences dipole-dipole interactions. Br2 forms hydrogen bonds. ICl experiences induced dipole-induced dipole interactions.

7 0

3 years ago

What is the name of the compound with the formula NaOH ?

vladimir2022 [97]

Answer:

Sodium hydroxide

Explanation:

Sodium hydroxide ( NaOH ) -

Sodium hydroxide is an inorganic compound , and is also called caustic soda and lye .

It is an ionic compound , which is white in color and is in solid state .

The cation and anion of this salt are the sodium cation Na⁺ and the hydroxide anions OH⁻ .

It is highly basic in nature and is soluble in water , and when left open in air it can readily absorb moisture from the air , to form a hydrated sodium hydroxide .

4 0

3 years ago

Wine goes bad soon after opening because the ethanol ch3ch2oh in it reacts with oxygen gas o2 from the air to form water h2o and

lilavasa [31]

The balanced chemical equation of the reaction described above is,

C2H6O + O2 --> H2O + C2H4O2

If we have 3.84 g of oxygen, we divide by its molar mass.

n = (3.54 g Oxygen gas) x (1 mole O2/ 32 g O2)
n = 0.11 moles O2

Using ratio and proportion,

number of moles of ethanol = (0.11 moles O2) x (1 mole C2H6)
= 0.11 moles C2H6

Then, we multiply the calculated value to its molar mass, 46 grams /mol.
mass of ethanol = (0.11 mol) x (46 grams / mol)
= 5.06 grams

8 0

3 years ago

In this double replacement reaction, which are the products? hcl + naoh —> ______?

Anarel [89]

The answer is: " NaCl + H₂O " ; (or; write as: " H₂O + NaCl " ) .
________________________________________________________
Specifically:
_________________________________________________________

    HCl + NaOH —> NaCl + H₂O ;   or; write as:

   NaOH + HCl —> H₂O + NaCl .
_______________________________________________________
            This type of "double-replacement" reaction is called "neutralization".

             Since we are adding a strong acid to a strong base (reactants), we know that the product will be: 1) a salt ; and 2) water. Since we know one of the reactants will be "water" (H₂O) ; we can find the base (i.e. , the "remaining product") from selecting the "unused elements" to form the corresponding "salt".
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3 0

3 years ago

Read 2 more answers