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iren [92.7K]
4 years ago
7

Which of the following methods will usually cause a reaction to speed up? Combining the reactants at a lower temperature. Reduci

ng the concentration of reactants. Grinding one of the reactants into a powder. Removing the catalyst.
Chemistry
2 answers:
Aneli [31]4 years ago
6 0
Ans: grinding one of the reactants into a powder.

this increases the surface area and hence there would be more chances of collisions happening. therefore reaction rate would increase
vredina [299]4 years ago
3 0

The answer is A. Changing the temperature from 90ºC to 40ºC

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How to find kc from % ionization
Lunna [17]
Well, percent ionization, simply allows you to find X which is the change in amount of substance into the final amount, it is dependent on the initial concentration of the substance present that is being dissociated.

For example, if the percent dissociation of CH3COOH is 1.5 % for an initial concentration of 0.15, then to solve for x, you would need to write percent as a decimal and solve.

% dissociation = X/Concentration of substance dissociated

0.015 = X/0.15

X = 0.0025.

Now since you know X, use the ice tables to solve for concentrations of species at equilibrium and plug in Kc expression.
8 0
4 years ago
What is the gram formula mass (molar mass) of Silicon Tetrabromide? Write the formula first!
agasfer [191]

Answer:

SiBr₄= 347.7 g/mol

Explanation:

Gram formula mass:

Gram formula mass is the atomic mass of one mole of any substance.

It can be calculated by adding the mass of each atoms present in substance.

SiBr₄:

Atomic mass of Si = 28.1 amu

Atomic mas of Br = 79.9 amu

There are four atoms of Br = 79.9 ×4

There is one atom of Si = 28.1 × 1

Gram formula mass of SiBr₄:

SiBr₄ = 79.9 ×4 + 28.1 × 1

SiBr₄= 319.6 + 28.1

SiBr₄= 347.7 g/mol

6 0
3 years ago
A 100 ml graduated cylinder with an inside diameter of 3.2 cm contains 34.0 g of gasoline and 34.0 g of water. what is the combi
Ivahew [28]

The volume of cylinder is 100 mL, inner diameter is 3.2 cm thus, radius will be:

r=\frac{d}{2}=\frac{3.2 cm}{2}=1.6 cm

Volume of layer formed=\pi r^{2}h...... (1)

Volume of layer is also equal to sum of volume of gasoline and water.

Density of gasoline is 0.702 g/cm^{3} and mass is 34 g thus, volume of gasoline will be:

V=\frac{m}{d}=\frac{34 g}{0.702 g/cm^{3}}=48.43 cm^{3}

Now, density of water is 1 g/cm^{3} and mass is 34 g thus, volume of water will be:

V=\frac{m}{d}=\frac{34 g}{1 g/cm^{3}}=34 cm^{3}

Adding both the volumes, volume of layer will be:

Volume of layer=48.43 cm^{3}+34 cm^{3}=82.43cm^{3}

Putting the values in equation (1) to solve for height of the layer,

h=\frac{volume of layer}{\pi r^{2}}=\frac{82.43 cm^{3}}{3.14\times 1.6 cm\times 1.6 cm}=10.25 cm

Thus, height of layer is 10.25 cm

3 0
4 years ago
How many nitrogen atoms are in 4.24 x 1022 molecules of Ca (NO3)2 ?
horsena [70]

Answer:

                       8.48 × 10²² atoms of Nitrogen

Explanation:

                   Calcium Carbonate is an ionic compound made up to Calcium (Ca²⁺) and Nitrate (NO₃⁻) ions. Also, the subscript 2 after the closed bracket after NO₃ specifies that there are two moles of NO₃⁻ in calcium nitrate compound. Hence, in total we can say that this compound contain,

                                    1 atom of Calcium

                                    2 atoms of Nitrogen

                                    6 atoms of Oxygen

Therefore,

When,

              1 molecule of Ca(NO₃)₂ contains  =  2 atoms of Nitrogen

Then,

   4.24 × 10²² molecules of Ca(NO₃)₂ will contain  = X atoms of Nitrogen

Solving for X,

                      X  =  2 atoms × 4.24 × 10²² molecule / 1 molecule

                      X =  8.48 × 10²² atoms of Nitrogen

6 0
4 years ago
In standardizing the solution of aqueous sodium hydroxide, a chemist overshoots the end point and adds too much naoh(aq). would
irinina [24]

Answer: Concentration of NaOH calculated will be underestimated.

Explanation:

End point is an observational point , which tells us about the completion of reaction between the titrant (solution in burette) and titre(solution in conical flask) in titration experiment.

In this case , NaOH is titrant whose concentration is unknown.

M_1=\text{molarity of titre} , M_2=\text{molarity of NaOH}

V_1=\text{volume of titre} , V_2=\text{volume of NaOH}

M_1V_1=M_2V_2

M_2=\frac{M_1V_1}{V_2}....(1)

According to question a chemist overshoots the end point and adds to much of NaOH solution, which means increase in the value of V_2.

Then the value of M_2 in equation (1), will get lowered , which means that the concentration of NaOH was lower than that of the actual value. Hence underestimated concentration of NaOH.




8 0
3 years ago
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