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Bogdan [553]
3 years ago
13

Which of the following slogans connects Beuyer watches with the lifestyle of a successful businessman?

Mathematics
1 answer:
Tom [10]3 years ago
5 0
Beuyer keeps Zurich time even while closing a deal in Shanghai
is the correct answer

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3 equivalent ratios for 1/10
nataly862011 [7]

Answer:

So just as a fraction of 3/30 can be simplified to 1/10, a ratio of 3:30 (or 4:40, 5:50, 6:60 and so on) can be simplified to 1:10.

Step-by-step explanation:

4 0
3 years ago
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what is the measure of the vertex angle of an isosceles triangle if one of its base angles measures 48 degrees?
Vladimir79 [104]
180-2\cdot48=180-96=84
7 0
2 years ago
A circle has a diameter of 18 mm. What is its circumference?
Sloan [31]

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56.52mm

Step-by-step explanation:

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2 years ago
A machine shop produces metal frames on two different machines. The average daily production on machine 1 is 300 frames, and the
statuscvo [17]

Answer:

The daily shop productivity is 480 frames

Step-by-step explanation:

The daily machine productivity refers to the TOTAL production made in a day.

The problem says that a shop produces metal on two different machines. It means that you must take into account the daily production of each one for finding the total production.

The first machine produces 300 frames in a day.

The second machine produces 180 frames in a day too.

So, if the first and the second machines are working together in a single day, the TOTAL daily production is the sum of the production of each one.

production=300+180=480

Thus, the daily shop productivity is 480 frames

4 0
3 years ago
HELP ASAP!!!!! Given: Point B is on the perpendicular bisector of AC¯¯¯¯¯. BD¯¯¯¯¯ bisects AC¯¯¯¯¯ at point D. Prove: B is equid
Harlamova29_29 [7]

Answer:  Missing parts are,

In first blank,  AD\cong DC,

In second blank, SAS postulate

In third blank, CPCTC postulate

Step-by-step explanation:

Since, Here D is the mid point on the line segment AC.

And BD is a perpendicular to the line AC.

Therefore, In triangles ADB and CDB ( shown in figure)

AD\cong DC ( By the definition of mid point)

\angle BDA\cong \angle BDC ( right angles )

BD\cong BD ( reflexive)

Thus, By SAS ( side angle side )postulate,

\triangle ADB\cong \triangle CDB

So, by CPCTC( Corresponding parts of congruent triangles are congruent)

AB\cong CB

Now, By definition of congruent segment,

AB=CB

By definition of equidistant,

B is equally far from both A and C.




7 0
2 years ago
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