<span>6.1875 inches would be 9 / 16 ths of 11 inches
</span>
Let’s say it takes time t hours for the interception.
In that time the carrier travels 28t nm west and the helicopter 130t nm.
Now we use the sine rule to find the angle x which lies between the distance 175 and 130t.
sin(x)/28t=sin35/130t. So sin(x)=28sin35/130=14sin35/65=0.1235 and x=7.0964 degrees.
Therefore the helicopter should use a bearing of 35+7.0964=42.0964 degrees north of east or 47.9 degrees east of north approx.
Answer: -9y
Step-by-step explanation:
Step1: -3 is multiplied by y = -3y
Step 2: -3 multiplied by 2 = -6
Step 3: -3y + -6
32.17/7 =
about 4.59571428571429
are there any instructions on rounding it to the nearest tenth, hundredths, etc.?
Answer:
V≈2144.66in³
Step-by-step explanation: