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3 years ago

12

Segment HK is 24 inches long.

1 answer:

Sunny_sXe [5.5K]3 years ago

6 0

The longitude of segment HL is 12 inches because its the half of segment HK which is 24.

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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Consider the functions given below. SEE F

Wewaii [24]

Answer:

1. $P(x)$ ÷ $Q(x)$ ---> $\frac{-3x + 2}{3(3x - 1)}$

2. $P(x) + Q(x)$ ---> $\frac{2(6x - 1)}{(3x - 1)(-3x + 2)}$

3. $P(x) - Q(x)$ ---> $\frac{-2(12x - 5)}{(3x - 1)(-3x + 2)}$

4. $P(x)*Q(x)$ --> $\frac{12}{(3x - 1)(-3x + 2)}$

Step-by-step explanation:

Given that:

1. $P(x) = \frac{2}{3x - 1}$

$Q(x) = \frac{6}{-3x + 2}$

Thus,

$P(x)$ ÷ $Q(x)$ = $\frac{2}{3x - 1}$ ÷ $\frac{6}{-3x + 2}$

Flip the 2nd function, Q(x), upside down to change the process to multiplication.

$\frac{2}{3x - 1}*\frac{-3x + 2}{6}$

$\frac{2(-3x + 2)}{6(3x - 1)}$

$= \frac{-3x + 2}{3(3x - 1)}$

2. $P(x) + Q(x)$ = $\frac{2}{3x - 1} + \frac{6}{-3x + 2}$

Make both expressions as a single fraction by finding, the common denominator, divide the common denominator by each denominator, and then multiply by the numerator. You'd have the following below:

$\frac{2(-3x + 2) + 6(3x - 1)}{(3x - 1)(-3x + 2)}$

$\frac{-6x + 4 + 18x - 6}{(3x - 1)(-3x + 2)}$

$\frac{-6x + 18x + 4 - 6}{(3x - 1)(-3x + 2)}$

$\frac{12x - 2}{(3x - 1)(-3x + 2)}$

$= \frac{2(6x - 1}{(3x - 1)(-3x + 2)}$

3. $P(x) - Q(x)$ = $\frac{2}{3x - 1} - \frac{6}{-3x + 2}$

$\frac{2(-3x + 2) - 6(3x - 1)}{(3x - 1)(-3x + 2)}$

$\frac{-6x + 4 - 18x + 6}{(3x - 1)(-3x + 2)}$

$\frac{-6x - 18x + 4 + 6}{(3x - 1)(-3x + 2)}$

$\frac{-24x + 10}{(3x - 1)(-3x + 2)}$

$= \frac{-2(12x - 5}{(3x - 1)(-3x + 2)}$

4. $P(x)*Q(x) = \frac{2}{3x - 1}* \frac{6}{-3x + 2}$

$P(x)*Q(x) = \frac{2*6}{(3x - 1)(-3x + 2)}$

$P(x)*Q(x) = \frac{12}{(3x - 1)(-3x + 2)}$

4 0

4 years ago

Which statement is NOT true? A. All isosceles triangles are also equilateral triangles. B. All equilateral triangles are also is

Alecsey [184]

Hello there!

The statement that would NOT be true would be option A. All isosceles triangles are also equilateral triangles. The rest of the statements would be TRUE.

Hope this helps and have a great day! :)

5 0

4 years ago

Solve for q.<br><br> 3/5 = q/10<br><br> q=?

Helga [31]

Simply the equation by using cross-multiplication, you get 30=5q
Then you swap sides of the equation, you get 5q=30
Then you divide both sides of the equation by 5
Your answer is q=6

4 0

3 years ago

The lunch room at Diane’s school has a perimeter of 300 feet. The length of the room is 85 feet. What is the width of the room?

Mumz [18]

Answer:

65

Step-by-step explanation:

2w+ 2l = 300

2w + 170=300

2w= 130

w=65

3 0

3 years ago

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Jackson and his 4 friends split the bill at a restaurant. The bill was $56.85. How much will each of them pay?

Marina CMI [18]

Answer:14.2

Step-by-step explanation:

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7 0

2 years ago

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