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4 years ago

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A DJ randomly selects 2 of 8 ads to play before her show. Two of the ads are by a local retailer. What is the probability that s

he will play both of the retailer's ads before her show? Enter your answer in simplified fraction form; example: 3/20

1 answer:

Katena32 [7]4 years ago

8 0

1/4 because there is 2 LR ads and 6 other ads, making a total of 8 and 2/8 simplifies to 1/4. Hope this helped!

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When the outliers are removed, how does the mean change?

jok3333 [9.3K]

<span>In statistics, an outlier is an observation point that is distant from other observations.

Given the points
15, 23, 24, 26, 27 and 35

Notice, that the points 15 and 35 are distance from the other points and hence are outliers.

The mean of the observations including the outliers is given by
$\frac{15+23+24+26+27+35}{6} = \frac{150}{6} =25$

The mean of the observations without the outliers is given by
$\frac{23+24+26+27}{4} = \frac{100}{4} =25$

Therefore, </span>when <span>the outliers are removed, the mean remains the same.</span>

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3 years ago

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What will the equation be if f(x)= x^2 is translated 6 units left and 3 units up?

zloy xaker [14]

Answer:

(x+6)^2+3

Step-by-step explanation:

translate 6 left

left is negative

so (x+6)^2. it is + because the x goes in the opposite direction causing (x-6)^2 to go right

and 3 units up so add x by 3 to get (x+6)^2+3

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2 years ago

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A farmer wants to mow two rectangular garden of dimensions 14 m × 12 m and 15m × 10m. Find the cost of mowing both the gardens a

Anit [1.1K]

Answer:

What is the cost per sq.m

Step-by-step explanation:

You can’t solve this without the cost per meter

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3 years ago

what is the total cost of a meal if the food cost $25 and there is a food tax of 3% and the waiter is tipped 15% of the food cos

Degger [83]

Answer:

$30

Step-by-step explanation:

If $25 is 100%,

$2.5 is 10%

$0.25 is 1%

$3.75 is 15%

$0.75 is 3%

Then add $25, $3.75 and 0.75 which is also equivalent to 100%+15%+3%=29.5 and if you rounded it up to the nearest cent it is 30

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3 years ago

The half-life of cesium-137 is 30 years. Suppose we have a 180-mg sample. (a) Find the mass that remains after t years. (b) How

DedPeter [7]

Answer:

a) $Q(t) = 180e^{-0.023t}$

b) 11.4mg of cesium-137 remains after 120 years.

c) 225.8 years.

Step-by-step explanation:

The following equation is used to calculate the amount of cesium-137:

$Q(t) = Q(0)e^{-rt}$

In which Q(t) is the amount after t years, Q(0) is the initial amount, and r is the rate at which the amount decreses.

(a) Find the mass that remains after t years.

The half-life of cesium-137 is 30 years.

This means that Q(30) = 0.5Q(0). We apply this information to the equation to find the value of r.

$Q(t) = Q(0)e^{-rt}$

$0.5Q(0) = Q(0)e^{-30r}$

$e^{-30r} = 0.5$

Applying ln to both sides of the equality.

$\ln{e^{-30r}} = \ln{0.5}$

$-30r = \ln{0.5}$

$r = \frac{\ln{0.5}}{-30}$

$r = 0.023$

So

$Q(t) = Q(0)e^{-0.023t}$

180-mg sample, so Q(0) = 180

$Q(t) = 180e^{-0.023t}$

(b) How much of the sample remains after 120 years?

This is Q(120).

$Q(t) = 180e^{-0.023t}$

$Q(120) = 180e^{-0.023*120}$

$Q(120) = 11.4$

11.4mg of cesium-137 remains after 120 years.

(c) After how long will only 1 mg remain?

This is t when Q(t) = 1. So

$Q(t) = 180e^{-0.023t}$

$1 = 180e^{-0.023t}$

$e^{-0.023t} = \frac{1}{180}$

$e^{-0.023t} = 0.00556$

Applying ln to both sides

$\ln{e^{-0.023t}} = \ln{0.00556}$

$-0.023t = \ln{0.00556}$

$t = \frac{\ln{0.00556}}{-0.023}$

$t = 225.8$

225.8 years.

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3 years ago

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