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Serga [27]
3 years ago
10

Troy sold 28 bags of popcorn and 40 candy bars and made $282. Jake sold 17 bags of popcorn and 20 bags of candy and made $160.50

. What was the cost of a bag of popcorn?
Mathematics
1 answer:
Ghella [55]3 years ago
3 0
One bag of popcorn would cost $6.50

To solve this, we can set up equations:
28p+40c=$282
17p+20c=$160.50

To solve this system, we would need to make either the candy bars the same or the bags of popcorn the same. Since we are solving for bags of popcorn, we will make the candy bars the same:
20(28p+40c=$282)
40(17p+20c=$160.50)

Which would give you:
560p+800c=$5,640
680p+800c=$6,420

Subtract them:
 (680p+800c=$6,420)
-(560p+800c=$5,640)
_________________
120p=$780

Now divide by 120 to get the price of one bag of popcorn:
120p=$780
_________
       120

p=$6.50
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jasenka [17]
It would help if you find common denominator... 12
so 1/3 times 4 both the numerator and denominator
4/12

and 3/4 times by 3 both the numerator and denominator
9/12

the recipe calls for 4/12 cup of oil and you have 9/12

two batches would be 8/12 cups of oil, you have 9/12 that is just enough for the recipe for two batches...

now to simplify it again, 1/3 + 1/3 = 2/3 and 2/3 is less than 3/4 
the answer would be the upper right
3 0
3 years ago
Read 2 more answers
1. is this a function 7 8 2 9 3 10​
kow [346]
I need a lil more information
7 0
2 years ago
If you could help I would really appreciate it, but if not that’s fine. Thank you.
Svetradugi [14.3K]
Since 4 is between 2 & 5 you input it into the middle equation.

x=4

so the answer is 4!
7 0
2 years ago
Identify whether the equation represents an exponential growth or exponential decay function.1. y = 1/4 (1/e)^-2x2. y = (1/e)^4x
zvonat [6]

The general formula for exponential growth and decays is:

y=y_0e^{kx}

if k>0 then then it is an exponential growth function. If k<0 then the function represents an exponential decay.

Now we need to classify each of the functions:

1.

The function

y=\frac{1}{4}(\frac{1}{e})^{-2x}

can be wrtten as:

\begin{gathered} y=\frac{1}{4}(e^{-1})^{-2x}^{} \\ =\frac{1}{4}e^{2x} \end{gathered}

comparing with the general formula we notice that k=2, therefore this is an exponential growth.

2.

The function

y=(\frac{1}{e})^{4x}

can be written as:

\begin{gathered} y=(\frac{1}{e})^{4x} \\ y=(e^{-1})^{4x} \\ y=e^{-4x} \end{gathered}

comparing with the general formula we notice that k=-4, therefore this is an exponential decay.

3.

The function

y=2e^{-x}+1

comparing with the general formula we notice that k=-1, therefore this is an exponential decay.

5 0
1 year ago
Which expression is equivalent to (x^2 -8) - (-2x^2+4)?​
Phoenix [80]

Answer:

D) 3x^2 - 12

Step-by-step explanation:

Using PEMDAS;

There is no need to evaluate the part of the equation (x^2 - 8) because is no need to, as it is already in its simplest form.

We must evaluate the part of the equation continuing with, "- (-2x^2+4)," as it is not in its simplest form.

Evaluating "- (-2x^2+4)":

Step 1: Distributing the negative

Once distributing the negative symbol amongst the values within the parenthesis according to PEMDAS, we get "2x^2 - 4" as the product.

Step 2: Consider the rest of the equation to evaluate

Since the part of the equation is still in play here as it is a part of the original equation to be solved, we must evaluate it as a whole to get the final answer.

Thus,

x^2 -8 + 2x^2 - 4 = ___

*we can remove the parenthesis as it has no purpose, since it makes no difference.

Evaluating for the answer, we get,

x^2+2x^2 + (-8 - 4) = 3x^2 - 12

Hence, the answer is D) 3x^2 - 12.

3 0
3 years ago
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