Answer:
12x+3 / 4x
Step-by-step explanation:
Answer:
32.6
Step-by-step explanation:
Look at the decimal in the hundredths place in 32.62
If the number is 0-4, round down. If the number is 5-9, round up.
In 32.62, the number in the hundredths place is 2. So, we round down to 32.6
<span>Assuming that the particle is the 3rd
particle, we know that it’s location must be beyond q2; it cannot be between q1
and q2 since both fields point the similar way in the between region (due to
attraction). Choosing an arbitrary value of 1 for L, we get </span>
<span>
k q1 / d^2 = - k q2 / (d-1)^2 </span>
Rearranging to calculate for d:
<span> (d-1)^2/d^2 = -q2/q1 = 0.4 </span><span>
<span> d^2-2d+1 = 0.4d^2 </span>
0.6d^2-2d+1 = 0
d = 2.72075922005613
d = 0.612574113277207 </span>
<span>
We pick the value that is > q2 hence,</span>
d = 2.72075922005613*L
<span>d = 2.72*L</span>
Answer:
a = π n for n element Z
Step-by-step explanation:
Solve for a:
sec(a) + tan(a) = sec(a) - tan(a)
Subtract sec(a) - tan(a) from both sides:
2 tan(a) = 0
Divide both sides by 2:
tan(a) = 0
Take the inverse tangent of both sides:
Answer: a = π n for n element Z