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julsineya [31]
3 years ago
13

Find the slope of a line PERPENDICULAR TO LM: L(3,-5), M(-4, -1)

Mathematics
1 answer:
Ede4ka [16]3 years ago
7 0

Answer:

\frac{7}4

Step-by-step explanation:

First, we need to find the slope, which is defined as the change in y over the change in x:

\frac{-5-(-1)}{3-(-4)} = \frac{-4}{7}

To find a slope that's perpendicular to that, we just take the negative reciprocal of that slope, which is \frac{7}4.

I hope this helped.

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AD←→ is tangent to circle M at point D. The measure of ∠DMQ is 58º.
Marat540 [252]

Answer:

32°

Step-by-step explanation:

Given:

∠DMQ = 58º

In this circle, the radius is DM. Since AD is tangent to the circle M, at point D, and the angle between a tangent and a radius is 90°

Therefore, ∠MDQ = 90°

The total angle in a triangle is 180°. Since we have the values of ∠MDQ and ∠DMQ, ∠DQM will be calculated as:

180 = ∠DMQ + ∠MDQ + ∠DQM

Solving for ∠DQM, we have:

∠DQM = 180 - ∠DMQ - ∠MDQ

∠DQM = 180 - 90 - 58

∠DQM = 32°

The measure of ∠DQM is 32°

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Sveta_85 [38]
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Answer:

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Step-by-step explanation:

Given: AB = BA = I

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