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2 years ago

Find the slope of a line PERPENDICULAR TO LM: L(3,-5), M(-4, -1)

Mathematics

1 answer:

Ede4ka [16]2 years ago

7 0

Answer:

$\frac{7}4$

Step-by-step explanation:

First, we need to find the slope, which is defined as the change in y over the change in x:

$\frac{-5-(-1)}{3-(-4)} = \frac{-4}{7}$

To find a slope that's perpendicular to that, we just take the negative reciprocal of that slope, which is $\frac{7}4$ .

I hope this helped.

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How many solutions does the equation have?

Dovator [93]

$3(4x-3)-7x=5x-9\\\\3(4x)+3(-3)-7x=5x-9\\\\12x-9-7x=5x-9\\\\\boxed{5x-9=5x-9}\\\\conclusion:\boxed{B.\ infinite\ solutions}$

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3 years ago

Read 2 more answers

What is the perimeter of this rectangle?

givi [52]

The perimeter is defined as the sum of all the sides of any polygon.

A rectangle is a polygon with 4 sides and 2 pairs of parallel sides. Therefore, in order to find the perimeter of any rectangle, we can either add up all the sides given to you or use a formula which states that:

P = 2L + 2W
Where,
L is the length of the rectangle and W is the width of a triangle.

For example:
A triangle with length = 5 cm and Width = 3 cm.
The Perimeter will be:
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3 years ago

You spin a spinner that is equally divided into 7 parts. 2 parts white, 2 parts are speckled, and 3 parts are blue.

kap26 [50]

Answer:

3/7

Step-by-step explanation:

you are gonna add all the parts together which is seven and because three parts are blue chances are that it might stop at blue three times out of seven

6 0

2 years ago

Need help on numbers 10 and 11 please!! sos

Harlamova29_29 [7]

Volume of prism B=800*6³/8³
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5 0

3 years ago

A professor records the difference between the marks scored by the students in the class test last week and those scored in the

dezoksy [38]

Answer: $(10.82\ , 13.18)$

Step-by-step explanation:

The confidence interval for population mean is given by :-

$\mu\pm\ z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}$

Given : Sample size : n= 35 , large sample (n>30)

Mean difference : $\overline{x}=12$

Standard deviation : $\sigma=3$

Significance level : $\alpha=- 1-0.999=0.001$

Critical value : $z_{\alpha/2}=z_{0.0005}=3.4807567$

Now, the 99.9% confidence interval for the mean difference between the marks scored last week and marks scored this week by all the students will be :-

$12\pm\ (3.4807567)\dfrac{2}{\sqrt{35}}\\\\=12\pm1.18\\\\=(10.82\ , 13.18)$

Hence, the 99.9% confidence interval for the mean difference between the marks scored last week and marks scored this week by all the students = $(10.82\ , 13.18)$

4 0

2 years ago