Hello!
The surface area is the area of all of the shapes on the net added up. First we will find the area of the two triangles.
A=0.5bh
A=0.5(3·6)
A=0.5(18)
A=9
Since there are two triangles we double this area, giving us 18.
Now let's find the length of the two side rectangles.
7(4)=28
28+28=56
Now to find the middle rectangle.
6(7)=42
Now we add up all of the area to find the surface area.
42+56+18=116
The surface area is 116 cm².
I hope this helps!
Option D:
A = 1, B = –3 and C = 4.
Solution:
Given equation is x – 3y + 4 =0.
General equation of a line format:
<em>Ax + By + C = 0</em>
<u>To identify A, B and C in the given equation:</u>
x – 3y + 4 =0 is a equation of a line which is in the form of Ax + By + C = 0.
That is,
The coefficient of x is A ⇒ A = 1
The coefficient of y is B ⇒ B = –3
The constant term is C ⇒ C = 4
A = 1, B = –3 and C = 4.
Hence Option D is the correct answer.
Answer:
3 , 1 , -1 , -3
Step-by-step explanation:
5 - 2n
n = 1 ; 5 - 2n = 5 - 2*1 = 5 - 2 = 3
n = 2; 5 - 2n = 5 - 2*2 = 5 - 4 = 1
n = 3; 5 - 2n = 5 - 2*3 = 5 - 6 = -1
n = 4; 5 -2n = 5 - 2*4 = 5 - 8 = -3
First 4 terms are : 3 , 1 , -1 , -3
Given:ABCD is a rhombus.
To prove:DE congruent to BE.
In rombus, we know opposite angle are equal.
so, angle DCB = angle BAD
SINCE, ANGLE DCB= BAD
SO, In triangle DCA
angle DCA=angle DAC
similarly, In triangle ABC
angle BAC=angle BCA
since angle BCD=angle BAD
Therefore, angle DAC =angle CAB
so, opposite sides of equal angle are always equal.
so,sides DC=BC
Now, In triangle DEC and in triangle BEC
1. .DC=BC (from above)............(S)
2ANGLE CED=ANGLE CEB (DC=BC)....(A)
3.CE=CE (common sides)(S)
Therefore,DE is congruent to BE (from S.A.S axiom)
