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sladkih [1.3K]
3 years ago
9

Please I need to know today?

Mathematics
1 answer:
GenaCL600 [577]3 years ago
8 0

Answer:

The three collinear poitns are D, A, and E.

Step-by-step explanation:

Collinear points are points that all reside on the same line. Since we are looking for 3 seperate points we need a line with 3 points. There are only 2 lines on the picture and only one has three lines getting you your answer.

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An alarming number of U.S. adults are either overweight or obese. The distinction between overweight and obese is made on the ba
madreJ [45]

Answer:

(A) The probability that a randomly selected adult is either overweight or obese is 0.688.

(B) The probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C) The events "overweight" and "obese" exhaustive.

(D) The events "overweight" and "obese" mutually exclusive.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = a person is overweight

<em>Y</em> = a person is obese.

The information provided is:

A person is overweight if they have BMI 25 or more but below 30.

A person is obese if they have BMI 30 or more.

P (X) = 0.331

P (Y) = 0.357

(A)

The events of a person being overweight or obese cannot occur together.

Since if a person is overweight they have (25 ≤ BMI < 30) and if they are obese they have BMI ≥ 30.

So, P (X ∩ Y) = 0.

Compute the probability that a randomly selected adult is either overweight or obese as follows:

P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\\=0.331+0.357-0\\=0.688

Thus, the probability that a randomly selected adult is either overweight or obese is 0.688.

(B)

Commute the probability that a randomly selected adult is neither overweight nor obese as follows:

P(X^{c}\cup Y^{c})=1-P(X\cup Y)\\=1-0.688\\=0.312

Thus, the probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C)

If two events cannot occur together, but they form a sample space when combined are known as exhaustive events.

For example, flip of coin. On a flip of a coin, the flip turns as either Heads or Tails but never both. But together the event of getting a Heads and Tails form a sample space of a single flip of a coin.

In this case also, together the event of a person being overweight or obese forms a sample space of people who are heavier in general.

Thus, the events "overweight" and "obese" exhaustive.

(D)

Mutually exclusive events are those events that cannot occur at the same time.

The events of a person being overweight and obese are mutually exclusive.

5 0
3 years ago
If x is equal to –2, then find the value of 3x² + 5x​
attashe74 [19]

Answer:

2

Step-by-step explanation:

3*(-2)to power of 2 + 5*-2

= 3*4 + 5*-2

= 12 + -10 = 2

5 0
3 years ago
Jill had $125 to spend at the mall. She spent 27% of that money on a pair of shoes. Jill spent $___ on the shoes.
zaharov [31]
You need to find what 27% of $125 is.
To find a percent of a number, multiply the percent by the number.

27% of $125 =

= 27% * $125

= 0.27 * $125

= $33.75

Answer: Jill spent $33.75 on the shoes.
4 0
3 years ago
PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER PLS ANSWER THE QUESTION WITH A STEP BY STEP EX
Marina CMI [18]

i think the correct answer is C

5 0
2 years ago
Read 2 more answers
Como realizar esa operación matemática
LenaWriter [7]

Simplemente necesitas restar tres de siete y dejar tu denominador como 4. Tu respuesta es 4/4, que es lo mismo que 1.

5 0
3 years ago
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