Answer:
Step-by-step explanation:
We have to diagonalize the matrix
we have to solve the expression
Thus, by applying the determinant we obtain the polynomial
and the eigenvector will be
HOPE THIS HELPS!!
Rewrite cot 80° in terms of its cofunction.
1 answer:
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The roots of the entire <em>polynomic</em> expression, that is, the product of p(x) = x^2 + 8x + 12 and q(x) = x^3 + 5x^2 - 6x, are <em>x₁ =</em> 0, <em>x₂ =</em> -2, <em>x₃ =</em> -3 and <em>x₄ =</em> -6.
<h3>How to solve a product of two polynomials </h3>
A value of <em>x</em> is said to be a root of the polynomial if and only if <em>r(x) =</em> 0. Let be <em>r(x) = p(x) · q(x)</em>, then we need to find the roots both for <em>p(x)</em> and <em>q(x)</em> by factoring each polynomial, the factoring is based on algebraic properties:
<em>r(x) =</em> (x + 6) · (x + 2) · x · (x² + 5 · x - 6)
<em>r(x) =</em> (x + 6) · (x + 2) · x · (x + 3) · (x + 2)
r(x) = x · (x + 2)² · (x + 3) · (x + 6)
By direct inspection, we conclude that the roots of the entire <em>polynomic</em> expression are <em>x₁ =</em> 0, <em>x₂ =</em> -2, <em>x₃ =</em> -3 and <em>x₄ =</em> -6.
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