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Oksi-84 [34.3K]
3 years ago
12

Which experimental setup would let a student investigate the connection between kinetic energy and temperature? (1 point) placin

g one drop of food coloring in a cup with 60 ml of water at 10",placing one drop of od coloring in a second oup with 60 mL of water at 40°C placing one drop of food coloring in a cup with 50 ml of water at 10" placing one drop of food coloring in a second cup with 100 ml of water al 10" placing one drop of food coloring in a cup with some of water al 10 placing two drops of food coloring in a second cup with 100 ml of water an 100 placing one drop of food coloring in a cup with some of water at 100 placing two drops of food coloring in a second cup with 50 ml of water at To ONO type here to search​
Chemistry
1 answer:
Maslowich3 years ago
5 0

Answer:

The correct option is;

Placing one drop of food coloring in a cup with 60 ml of water at 10°, placing one drop of food coloring in a second cup with 60 ml of water at 40°C

Explanation:

The experimental setup that would allow the student investigate the connection between kinetic energy and temperature should be made up of the following characteristics

1) The constant terms for the experiment should be defined, which in this case are

a) The volume of the water which is 60 ml in both subjects of the experiment

2) The definition of the variable that produces the effect that is being monitored, which is the use of the different temperatures in the two experimental subjects

3)The environmental limits of the experiment, which is the water and the food coloring used

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Which element is used for the shiny trim on cars
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3 years ago
Cryolite, Na3AlF6(s), an ore used in the production of aluminum, can be synthesized using aluminum oxide. Balance the equation f
dmitriy555 [2]

<u>Answer:</u> The mass of cryolite produced is 51.48 kg

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • <u>For aluminium oxide:</u>

Given mass of aluminium oxide = 12.5 kg = 12500 g    (Conversion factor:  1 kg = 1000 g)

Molar mass of aluminium oxide = 101.96 g/mol

Putting values in equation 1, we get:

\text{Moles of aluminium oxide}=\frac{12500g}{101.96g/mol}=122.6mol

  • <u>For NaOH:</u>

Given mass of NaOH = 55.4 kg = 55400 g

Molar mass of NaOH = 40 g/mol

Putting values in equation 1, we get:

\text{Moles of NaOH}=\frac{55400g}{40g/mol}=1389mol

  • <u>For HF:</u>

Given mass of HF = 55.4 kg = 55400 g

Molar mass of HF = 20 g/mol

Putting values in equation 1, we get:

\text{Moles of HF}=\frac{55400g}{20g/mol}=2770mol

For the given chemical reaction:

Al_2O_3(s)+6NaOH(l)+12HF(g)\rightarrow 2Na_3AlF_6+9H_2O(g)

By Stoichiometry of the reaction:

1 mole of aluminium oxide reacts with 6 moles of sodium hydroxide and 12 moles of HF.

So, 122.6 moles of aluminium oxide will react with (6\times 122.6)=735.6mol of sodium hydroxide and (12\times 122.6)=1471.2mol of HF

As, given amount of NaOH and HF is more than the required amount. So, they are considered as an excess reagent.

Thus, aluminium oxide is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of aluminium oxide produces 2 moles of cryolite

So, 122.6 moles of aluminium oxide will produce = \frac{2}{1}\times 122.6=245.2mol of cryolite

Now, calculating the mass of cryolite by using equation 1:

Molar mass of cryolite = 209.94 g/mol

Moles of cryolite = 245.2 mol

Putting values in equation 1, we get:

245.2mol=\frac{\text{Mass of cryolite}}{209.94g/mol}\\\\\text{Mass of cryolite}=(245.2mol\times 209.94g/mol)=51477.3g

Converting this into kilograms, we use the conversion factor:

1 kg = 1000 g

So, 51477.3 g\times (\frac{1kg}{1000g})=51.48kg

Hence, the mass of cryolite produced is 51.48 kg

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