If you dilute 745 mL of a 5.0 M solution of Mgl, to 3.0 L, determine the new

What takes place during a redox reaction

VladimirAG [237]

Electrons are both gained and lost.

7 0

3 years ago

Devante buys a helium birthday balloon for his mom at the grocery store, where the temperature is a comfortable 72oF. He takes t

frozen [14]

The balloon would be smaller and not float as well because of the low temperature. The particles in the balloon when in the car will slow down and get closer together because of the low temperature. That caused it to become more dense and smaller in size then before. When in the store, the particulars in the balloon we’re moving faster and more spread apart

5 0

4 years ago

A piece of wood has a labeled length value of 63.2 cm. You measure its length three times and record the following data: 63.1 cm

Ulleksa [173]

Percent error (%)= $\frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100$

Accepted value is true value.

Measured values is calculated value.

In the question given Accepted value (true value) = 63.2 cm

Given Measured(calculated values) = 63.1 cm , 63.0 cm , 63.7 cm

1) Percent error (%) for first measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.1 cm

Percent error (%)= $\frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100$

$Percent error = \frac{\left | 63.2 - 63.1 \right |}{63.2}\times 100$

$Percent error = \frac{0.1}{63.2}\times 100$

$Percent error = 0.00158\times 100$

Percent error = 0.158 %

2) Percent error (%) for second measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.0 cm

Percent error (%)= $\frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100$

$Percent error = \frac{\left | 63.2 - 63.0 \right |}{63.2}\times 100$

$Percent error = \frac{0.2}{63.2}\times 100$

$Percent error = 0.00316\times 100$

Percent error = 0.316 %

3) Percent error (%) for third measurement.

Accepted value (true value) = 63.2 cm, Measured(calculated values) = 63.7 cm

Percent error (%)= $\frac{\left | Accepted value - Measured value \right |}{Accepted value}\times 100$

$Percent error = \frac{\left | 63.2 - 63.7 \right |}{63.2}\times 100$

$Percent error = \frac{\left | -0.5 \right |}{63.2}\times 100$

$Percent error = \frac{(0.5)}{63.2}\times 100$

$Percent error = 0.00791\times 100$

Percent error = 0.791 %

Percent error for each measurement is :

63.1 cm = 0.158%

63.0 cm = 0.316%

63.7 cm = 0.791%

7 0

4 years ago

Would the ph at the equivalence point be acidic, basic, or neutral for each given titration?.

Lesechka [4]

Answer:

At the equivalence point, equal amounts of H+ and OH– ions will combine to form H2O, resulting in a pH of 7.0 (neutral). The pH at the equivalence point for this titration will always be 7.0, note that this is true only for titrations of strong acid with strong base.

Explanation:

3 0

2 years ago

Which of the following pairs consists of a weak acid and a strong base? (1 point)

notka56 [123]

Answer:

acetic acid, sodium hydroxide

Explanation:

A strong acid is an acid that ionizes in water to give all its hydrogen ion. Weak acid only ionize to a certain degree. Acetic acid (CH3COOH) only ionize to give one hydrogen ion despite having other hydrogen atom. This account for its weak nature as an acid as shown below:

CH3COOH <=> H^+ + CH3COO^-

A strong base is a base that ionizes in water to give all it hydroxide ion. Sodium hydroxide(NaOH) ionizes to give all its hydroxide ions. This make it a strong base as shown below;

NaOH <=> Na^+ + OH^-

8 0

3 years ago