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3 years ago

A sample of 8.5 g nh3 on oxidation produces 4.5 g of no. calculate the percent yield. reaction: 4 nh3 5 o2 → 4 no 6 h2o

1 answer:

5 0

30.% Determine the molar mass of NH3 and NO Atomic weight nitrogen = 14.0067 Atomic weight hydrogen = 1.00794 Atomic weight oxygen = 15.999 Molar mass NH3 = 14.0067 + 3 * 1.00794 = 17.03052 g/mol Molar mass NO = 14.0067 + 15.999 = 30.0057 g/mol Moles NH3 = 8.5 / 17.03052 = 0.499103962 mol Moles NO = 4.5 / 30.0057 = 0.149971505 mol Looking at the balanced equation, for every mole of NH3 consumed, you should get one mole of NO. So if we had 100% yield, we should have 0.499103962 moles of NO. But we don't. The percent yield is a simple matter of division by what we did get by what we should get. So 0.149971505 / 0.499103962 = 0.300481497 = 30.0481497% Rounding to 2 significant figures gives 30.% yield.

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Makovka662 [10]

Answer:

elements tend not to react with other elements, there were no oxide compounds for Mendeleev to study. –Group 18 elements are generally unreactive. sodium ion is smaller because the sodium atom lost one electron. –An Na+ ion is smaller because it has one fewer electron shell.

Explanation:

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This is the chemical formula for methyl acetate: CH32CO2. Calculate the mass percent of hydrogen in methyl acetate. Round your a

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Answer: The mass percent of hydrogen in methyl acetate is 8 %

Explanation:

The given chemical formula of methyl acetate is $CH_3COOCH_3$

To calculate the mass percentage of hydrogen in methyl acetate, we use the equation:

$\text{Mass percent of hydrogen}=\frac{\text{Mass of hydrogen}}{\text{Mass of methyl acetate}}\times 100$

Mass of hydrogen = (6 × 1) = 6 g

Mass of methyl acetate = [(3 × 12) + (6 × 1) + (2 × 16)] = 74 g

Putting values in above equation, we get:

$\text{Mass percent of hydrogen}=\frac{6g}{74g}\times 100=8.10\%=8\%$

Hence, the mass percent of hydrogen in methyl acetate is 8 %

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A sample of rainwater is tested with the indicator bromothymol blue and it turns yellow. What is most likely PH of rainwater? 4,

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Answer:

Explanation:

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Drupady [299]

Explanation:

Standard formation of an substance is defined as formation of one mole of substance from its constituting elements.

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A balanced chemical equation for the standard formation reaction of solid chromium(III) nitrate

$Cr(s)+\frac{3}{2}N_2(g)+\frac{9}{2}O_2\rightarrow Cr(NO_3)_3(s)$

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3 years ago