Molarity after dilution : 0.0058 M
<h3>Further explanation </h3>The number of moles before and after dilution is the same
The dilution formula
M₁V₁=M₂V₂
M₁ = Molarity of the solution before dilution
V₁ = volume of the solution before dilution
M₂ = Molarity of the solution after dilution
V₂ = Molarity volume of the solution after dilution
M₁=0.1 M
V₁=6.11
V₂=105.12
Answer:- 324.3 grams.
Solution:- We have been given with 6.0 moles of nitrous acid and asked to calculate it's grams. Moles to grams is a unit conversion and for doing this conversion we multiply the given moles by the molar mass of the compound.
Molar mass is the formula mass and to calculate this the atomic masses of each atom are multiplied by their respective subscripts that is the number of the atom in the compound .
For example, has one nitrogen atom and one oxygen atom. So, the molar mass of this is = atomic mass of N + 2(atomic mass of O)
= 14 + 2(16)
= 14 + 32
= 46 gram per mol
gram per mol is the unit of molar mass. So, the molar mass of is 46 grams per mol.
Let's calculate the molar mass of nitrous acid using the same concept.
molar mass of [ = 1 + 14 + 2(16)
= 1 + 14 + 32
= 47 grams per mol
Now, 6.9 moles of nitrous acid could easily be converted to grams as:
= 324.3 g
Hence, the mass of 6.9 moles of nitrous acid is 324.3 grams.