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QveST [7]
3 years ago
15

Faces of a rectangular prism and a cude

Mathematics
1 answer:
Vladimir79 [104]3 years ago
5 0
There are 6 faces in a rectangular prism and cube*
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The graph of f(x) = 2x + 1 is shown below. Explain how to find the average rate of change between x = 0 and x = 2.
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The last description actually clarifies the given equation. The equation should be written as: f(x) = 2ˣ +1. The x should be in the exponent's place. 

The average rate of change, in other words, is the slope of the curve at certain points. In equation, the slope is equal to Δy/Δx. It means that the slope is the change in the y coordinates over the change in the x coordinate. So, we know the denominator to be: 2-0 = 2. To determine the numerator, we substitute x=0 and x=2 to the original equation to obtain their respective y-coordinate pairs.

f(0)= 2⁰+1 = 2
f(2) = 2² + 1 = 5

So, the slope is equal to:

Average rate of change = (5 - 2)/(2 - 0)
Average rate of change = 3/2 or 1.5
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Jill spends $525 for monthly bills. Of this amount she spends 110 on her cell phone bill and 25% on her car payment. The remaind
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damaskus [11]
The answer is 11/36

2/12 chance of rolling fours

because there are 2 sides containing a four on both dice combined and 12 sides in total.

Doubles mean you have to roll the same number simultaneously so let’s say we want to calculate the probability for double ones: then it’s 1/6 on the first dice for a one, and 1/6 on the second dice to land on a one as well.

I personally like to imagine a box like this:
_ _ _ _ _ _
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If you have one dice then it’s just a random segment on one of the lines. If you want the specific result from two dice then you want two specific segments which is also the 1 specific tile out of 36 (6 width times 6 height). So you multiply.

1/6 * 1/6 = 1/36 chance to roll double of ones

And 1/36 chance to roll double twos, threes, fours, fives, and sixes. But we don’t count the double fours because any four will do. So:

1/36 * 5 = 5/36

So for the probability of either doubles or containing a four is the probability of doubles of either number plus the probability of either dice being a four:

5/36 + 2/12 =

5/36 + 6/36 =

11/36
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