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Aleks04 [339]
3 years ago
5

A bakery the price of the cake is nine dollars more than the price of a pie. One day the bakery sold 8 cakes and 14 pies for a t

otal of $402. The system of equations below can be used to find c the cost in dollars of a cake and P the cost in dollars of a pie. What is the price of a cake?
Mathematics
1 answer:
gavmur [86]3 years ago
7 0

Answer:

The price of the cake is $24 and the price of the Pie is $15

Step-by-step explanation:

Given

<em>Represent price of Cake with C and Price of Pie with P</em>

C = 9 + P

Cakes sold = 8

Pies sold = 14

Total = \$402

Required

Determine C and P

To represent the cakes and pies sold, we have the following expression

8C + 14P = 402

Substitute 9 + P for C

8(9+P) + 14P = 402

Open the bracket

72 + 8P + 14P = 402

Collect Like Terms

8P + 14P = 402 - 72

22P= 330

Divide both sides by 22

P = \frac{330}{22}

P = 15

Recall that

C = 9 + P

C = 9 + 15

C = 24

<em>Hence, the price of the cake is $24 and the price of the Pie is $15</em>

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Brian invested the money for 6 years, so now let's check how much is that for the remaining 4 years.


\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &2035.3275\\ r=rate\to 4.9\%\to \frac{4.9}{100}\dotfill &0.049\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &4 \end{cases}


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B. is the answer to your question!! Hope this helps!! :D
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