Question

By using Kirchhoff's Laws, it can be shown that the currents I1, I2, and I3 that pass through the three branches of the circuit in the figure satisfy the given linear system. Solve the system to find I1, I2, and I3. (Round your answers to three decimal places.)
I(sub)1 + I(sub)2 − I3 = 0
8I(sub)1 − 4I(sub)2 = 2
4I(sub)2 + 2I(sub)3 = 8
R = 8, R2 = 4, R3 = 2
V = 2, V(sub)2 = 8 ...?

Answer 1

Solve the second equation for I_1 and the third equation for I_3. Then plug those into the first equation. From here you can solve for I_2. Then you can plug that in to equation 2 to solve for I_1. Then plug in to equation 3 to solve for I_3.