Airbags and safety belts can reduce injuries because they can

How much potential energy does a 40-kg medicine ball gain when it is lifted 5 m? Use the formula: GPE= mass X gravity (9.8 m/s2)

Ronch [10]

The answer is c: 1960 J

Potential Energy :
PE = m x g x h = 40*9.8*5=1960

4 0

3 years ago

1. Is there a relationship between the volume of water displaced and the total volume of the block that has anything to do with

strojnjashka [21]

Answer:

The volume of the block is equal to the volume of water displaced by the block.

Explanation:

Volume refers to the amount of space occupied by a given object (in this case the block). When an object such as the block is immersed in water, it displaces its own volume of water. This volume of water displaced is equal to the volume of the block. Hence we can write;

Final Volume of water - Initial Volume of water= Water Displaced = Volume of the block

Recall that the density of a body is given by;

Density= mass/volume

If we obtain the volume of the block by measuring the volume of water displaced by the block, then we weigh the block using a weighing balance, we can obtain the density of the block easily from the relationship shown above.

8 0

2 years ago

The radius of a planet is 2400 km, and the acceleration due to gravity at its surface is 3.6 m/s2.

kiruha [24]

Answer:

$3.1\cdot10^{23}\:\mathrm{kg}$

Explanation:

We can use Newton's Universal Law of Gravitation to solve this problem:

$g_P=G\frac{m}{r^2}$ ., where $g_P$ is acceleration due to gravity at the planet's surface, $G$ is gravitational constant $6.67\cdot 10^{-11}$ , $m$ is the mass of the planet, and $r$ is the radius of the planet.

Since acceleration due to gravity is given as $m/s^2$ , our radius should be meters. Therefore, convert $2400$ kilometers to meters:

$2400\:\mathrm{km}=2,400,000\:\mathrm{m}$ .

Now plugging in our values, we get:

$3.6=6.67\cdot10^{-11}\frac{m}{(2,400,000)^2}$ ,

Solving for $m$ :

$m=\frac{2,400,000^2\cdot3.6}{6.67\cdot 10^{-11}},\\m=\fbox{$3.1\cdot10^{23}\:\mathrm{kg}$}$ .

6 0

2 years ago

A speed boat moving at a velocity of 25 m/s runs out of gas and drifts to a stop 3 minutes later 100 meters away. What is its ra

mr_godi [17]

<h2>Answer:</h2>

The rate of deceleration is -0.14 $m/s^{2}$

<h2>Explanation:</h2>

Using one of the equations of motion;

v = u + at

where;

v = final velocity of the boat = 0m/s (since the boat decelerates to a stop)

u = initial velocity of the boat = 25m/s

a = acceleration of the boat

t = time taken for the boat to accelerate/decelerate from u to v = 3 minutes

Convert the time t = 3 minutes to seconds;

=> 3 minutes = 3 x 60 seconds = 180seconds.

Substitute the values of v, u, t into the equation above. We have;

v = u + at

=> 0 = 25 + a(180)

=> 0 = 25 + 180a

Make a the subject of the formula;

=> 180a = 0 - 25

=> 180a = -25

=> a = -25/180

=> a = -0.14 $m/s^{2}$

The negative value of a shows that the boat is decelerating.

Therefore, the rate of deceleration of the speed boat is 0.14 $m/s^{2}$

5 0

3 years ago

. Inside a laser apparatus, the stimulation and relaxation of electrons in atoms causes many photons with the same to be continu

mrs_skeptik [129]

Inside a laser apparatus, the stimulation and relaxation of electrons in atoms cause many photons with the same wavelength to be continuously emitted.

From the questions given, the main objective is to fill in the gaps and add important information where necessary. The missing information is highlighted in bold and underlined.

Inside a laser apparatus, the stimulation and relaxation of electrons in atoms cause many photons with the same wavelength to be continuously emitted.

2. When these photons are emitted, they travel between two reflective

surfaces to form the wave that is represented in the simulation.

3. This wave is the summation of all the photons being introduced with

every oscillation, and as they continue to travel, the amplitude

increases. 

4. This occurs because the photons are emitted in a coherent fashion;

however, amplitude when the photons overlap in an incoherent

fashion.

5. In a laser device, a small portion of photons are permitted to escape

(for use in an application). This is emulated in the simulation, by

settling the Damping to Lots such that amplitude remains relatively

constant when compared to damping of None. (Damping

represents the Loss of photons.

6. The generation of multiple wavelengths is possible in some laser

producing systems, and the diffraction angle can be varied to allow

the isolation of different wavelengths.

7. Finally, when the power of a laser is described, the wave property

that is being referenced is a function of its frequency and

amplitude.

Therefore, we can conclude that we've fully understood the concept of emission of photons and wavelength in a laser apparatus.

Learn more about wavelength here:

brainly.com/question/23023103?referrer=searchResults

5 0

2 years ago