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frosja888 [35]
3 years ago
9

Airbags and safety belts can reduce injuries because they can

Physics
1 answer:
pashok25 [27]3 years ago
5 0

Answer:

reduce the velocity of collision

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ABO blood group is a classification of blood depending on the presence of 4 different antigens.
grin007 [14]

Answer:

A

Explanation:

i feel it is correct

in the sense that it dwpends on the presence of 4different antigens

8 0
3 years ago
Read 2 more answers
Unmoving objects are being acted on by balance forces. TRUE or FALSE?
Reil [10]
True. There are forced acting on it, but as they're balanced it is unmoving
3 0
3 years ago
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A man is traveling on a bicycle at 14 m/s along a straight road that runs parallel to some railroad tracks. He hears the whistle
deff fn [24]

Answer:

Explanation:

b ) The problem is based on Doppler's effect of sound

f = f₀ x (V - v₀) /( V+v_s)

f is apparent frequency ,f₀ is real frequency , V is velocity of sound , v₀ is velocity of observer going away  , v_s is velocity of source going away

778  = 840 x (340 - 14)/ (340 + v_s)

340 + v_s = 341.18

v_s = 1.18 m /s

it will go  away from   the observer or the cyclist.

speed of train = 1.18 m /s

a )

For a stationary observer v₀ = 0

f = f₀ x V  /( V+v_s)

= 840 x 340 / (340 + 1.180)

= 837 Hz

6 0
3 years ago
Calculate the average velocity of a car that travels 555 km north east in 3.7 hours
Vera_Pavlovna [14]

Your answer:

150 kilometer's per hour.

7 0
3 years ago
A brick of mass 1.15 kg is attached to a thin (massless) cable and whirled around in a circle in a vertical plane. The circle ha
stira [4]

Explanation:

It is given that,

Mass of the brick, m = 1.15 kg

Radius of the circle, r = 1.44 m

The cable will break if the tension exceeds 43.0 N

Let v is the maximum sped can have at the bottom of the circle before the cable will break. At the bottom of the circle, the net force is equal to the centripetal force along with the weight of the brick. So,

T=\dfrac{mv^2}{r}+mg

\dfrac{T}{m}-g=\dfrac{v^2}{r}

v=\sqrt{(\dfrac{T}{m}-g)r}

v=\sqrt{(\dfrac{43}{1.15}-9.8)\times 1.44}

v = 6.30 m/s

So, the maximum speed of the brick at the bottom of the circle before the cable will break is 6.3 m/s. Hence, this is the required solution.

8 0
4 years ago
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