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3 years ago

Balance this equation- _SeCl6+_02>_SeO2+_Cl2

Chemistry

1 answer:

Dvinal [7]3 years ago

8 0

Answer:

Balanced chemical equation:

SeCl₆ + O₂ → SeO₂ + 3Cl₂

Explanation:

Chemical equation:

SeCl₆ + O₂ → SeO₂ + Cl₂

Balanced chemical equation:

SeCl₆ + O₂ → SeO₂ + 3Cl₂

The above equation is balanced. There are one Se, six chlorine and two oxygen atoms are present on both side of equation The given balanced equation followed the law of conservation of mass.

Law of conservation of mass:

According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.

Explanation:

This law was given by french chemist Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.

For example:

In given photosynthesis reaction:

6CO₂ + 6H₂O + energy → C₆H₁₂O₆ + 6O₂

there are six carbon atoms, eighteen oxygen atoms and twelve hydrogen atoms on the both side of equation so this reaction followed the law of conservation of mass.

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What does Einstein’s theory of relativity expalain?

anygoal [31]

Answer:

The correct answer is D. How gravity interacts with planets

Explanation:

Einstein's theory of relativity formulated in 1915 introduces the following concepts:

- Formula E = mc2 (relationship between energy, mass, speed of light)

- How nuclear energy is produced

-After seeing a solar eclipse, gravity is interpreted geometrically (which is an effect of distortion)

-Relative time

8 0

4 years ago

When an electron in a 2p orbital of a particular atom makes a transition to the 2s orbital, a photon of approximate wavelength 6

Mariulka [41]

Answer:

The energy difference between these 2p and 2s orbitals is $3.07\times 10^{-19} J$

Explanation:

Wavelength of the photon emitted = $\lambda =646.3 nm =646.3\times 10^{-9} m$

Energy of the photon will corresponds to the energy difference between 2p and 2s orbital = E

Energy of the photon is given by Planck's equation:

$E=\frac{hc}{\lambda }$

h = Planck's constant = $6.626\tiomes 10^{-34} Js$

c = Speed of the light = $3\times 10^8 m/s$

$E=\frac{6.626\tiomes 10^{-34} Js\times 3\times 10^8 m/s}{646.3\times 10^{-9} m}$

$E=3.07\times 10^{-19} J$

The energy difference between these 2p and 2s orbitals is $3.07\times 10^{-19} J$

3 0

4 years ago

How do catalysts function? A. They protect the products from external reactions. B. They increase the activation energy of an el

tamaranim1 [39]

The answer is C. They lower the activation energy of an elementary step of a reaction
This makes the reaction rate to increase since less energy is required to make a reaction occur.

3 0

3 years ago

A gas has a volume of 3L at 200 kPa. What will its volume be if the pressure is changed to 500 kPa?

marta [7]

Answer:

Explanation:

then it would be;

4L per 300kPa

5L per 400kPa

6L per 500kPa

that's how i'd work it out in my head, hope it helps, but not sure though!

5 0

3 years ago

U ever get an answer

den301095 [7]

Yesn’t. they are either wrong or links

6 0

2 years ago