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Dovator [93]
3 years ago
12

Consider the statement: “The temperature of the land is an important factor for the ripening of oranges, because it affects the

evaporation of water and the humidity of the surrounding air.” How many of these factors, temperature ripening evaporation humidity are physical properties or changes?
Chemistry
1 answer:
Alexxx [7]3 years ago
7 0
Physical Properties<span>: </span>Physical properties<span> can be observed or measured without changing the composition of matter. </span>Physical properties<span> are used to observe and describe matter. so physical changes are the change in temperature of the land and the evaporation of water and change humidity of the air. chemical change is the ripening of the orange</span>
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What volume (L) will 3.56 mol NH3 occupy at STP. (1 point)
mart [117]

Answer:

B

Explanation:

I hope it helps you good luck

7 0
3 years ago
If the pH of vinegar is 3.0, what is the concentration of H+ in vinegar?
Cerrena [4.2K]

Answer: The concentration of H^{+} ions in vinegar is 0.001 M.

Explanation:

Given: pH = 3.0

pH is the negative logarithm of concentration of hydrogen ion.

The expression for pH is as follows.

pH = - log [H^{+}]

Substitute the value into above expression as follows.

pH = - log [H^{+}]\\3.0 = - log [H^{+}]\\conc. of H^{+} = antilog (- 3.0)\\= 0.001 M

Thus, we can conclude that the concentration of H^{+} ions in vinegar is 0.001 M.

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3 years ago
Two hydrogen atoms collide in a head on collision and end up with zero kinetic energy. Each then emits a photon of 121.6 nm (n=2
Zinaida [17]

Explanation:

Expression for the kinetic energy is as follows.

         K.E = \frac{1}{2}mv^{2}

Now, total kinetic energy will be as follows.

    K.E = 2 \times \frac{1}{2}mv^{2} = m \times v^{2}

Since, this energy converts into electromagnetic radiation of wavelength 121.6 nm.

Relation between energy and photon is as follows.

   Energy of photon = \frac{hc}{\lambda}

                                = \frac{6.626 \times 10^{-34} \times 3 \times 10^{8}}{121.6 \times 10^{-9}}

                                 = 1.63 \times 10^{-18} J

    m \times v^{2} = 1.63 \times 10^{-18}

          v = \sqrt{\frac{1.63 \times 10^{-18}}{1.67 \times 10^{-27}}

             = 3.12 \times 10^{4} m/s

Thus, we can conclude that atoms were moving at a speed of 3.12 \times 10^{4} m/s before the collision.

8 0
3 years ago
Prform the following operation and express the answer in scientific notation 6.0 x 10^3-2.310^3
Marrrta [24]

The value 6.0 x 10^3- 2.3 × 10^3 in scientific notation is 3.7 × 10^3.

<h3> What is scientific notation?</h3>

Scientific notation is a way to write very large or very small numbers so that they are easier to read and work with.

You express a number as the product of a number greater than or equal to 1 but less than 10 and an integral power of 10 .

<h3>Why it is used? </h3>

There are two reasons to use scientific notation.

  • The first is to reveal honest uncertainty in experimental measurements.
  • The second is to express very large or very small numbers so they are easier to read.

Given,

= 6.0 x 10^3- 2.3 × 10^3

= (6.0 - 2.3) × 10^3

= 3.7 × 10^3

Thus, we find that the value 6.0 x 10^3- 2.3 × 10^3 in scientific notation is 3.7 × 10^3.

learn more about scientific notation :

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3 0
2 years ago
What is the percent composition of dinotrogen pentoxide? With work shown please
iris [78.8K]

Answer:

%N = 25.94%

%O = 74.06%

Explanation:

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We will multiply the molar mass of N by the number of N atoms in the formula of N₂O₅.

m(N): 2 × 14.01 g = 28.02 g

Step 2: Calculate the mass of oxygen in 1 mole of N₂O₅

We will multiply the molar mass of O by the number of O atoms in the formula of N₂O₅.

m(O): 5 × 16.00 g = 80.00 g

Step 3: Calculate the mass of 1 mole of N₂O₅

We will sum the masses of N and O.

m(N₂O₅) = m(N) + m(O) = 28.02 g + 80.00 g = 108.02 g

Step 4: Calculate the percent composition  of N₂O₅

We will use the following expression.

%Element = m(Element)/m(Compound) × 100%

%N = m(N)/m(N₂O₅) × 100% = 28.02 g/108.02 g × 100% = 25.94%

%O = m(O)/m(N₂O₅) × 100% = 80.00 g/108.02 g × 100% = 74.06%

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