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Kisachek [45]
4 years ago
6

All of the following statements about different elements are true EXCEPT:a) barium is an alkali earth metalb) manganese is a tra

nsition metal c) sulfur is considered a metalloid d) krypton is one of the noble gasses e) iodine is a halogen
Chemistry
1 answer:
stich3 [128]4 years ago
6 0

Answer:

  • The statement that is not true is: <u>c) Sulfur is considered a metalloid </u>

Explanation:

To answer this kind of questions your best tool is a periodic table.

The periodic table shows the <em>elements</em> ordered by increasing atomic number (number of protons), in an arragement of rows and columns. In such arrangement, the elements appear classified as metals, non-metals, and metaloids.

Roughly metals are on the left side of the table, nonmetals are on the right side, and metalloids are a reduced group that are in a kind of step ladder dividing the metals and nonmetals.

With that, you can follow this procedure for each of the answer choices:

<u><em>a) Barium is an alkali earth metal:</em></u>

TRUE. Barium, Ba, has atomic number 56, is in the column (group) number 2, which is the group of the alkali earth metals.

<u><em>b) Manganese is a transition metal:</em></u>

TRUE. Manganese, Mn, has atomic number 25 and is in the column 7. The columns 3 through 12 enclose the transition metals. So, manganese is a transition metal.

<u><em>c) Sulfur is considered a metalloid.</em></u>

FALSE. Sulfur, S, has atomic number 16, is in the column 16, (right below oxygen) and is classified as a nonmetal.

<u><em>d) Krypton is one of the noble gasses </em></u>

TRUE. Krypton, Kr, has atomic number 36, and is in the column 18. This column includes all the noble gases, which are elements whose valence shells are complete (2 electrons in the case of He and 8 electrons in all the other cases).

This group is named noble gases because the elements have very low reactivity, so they are almos inert.

<u><em>e) Iodine is a halogen</em></u>

TRUE. Iodine, I, is the element with atomic number 53, and is in the column 17. This column includes all the halogens (F, Cl, Br, I, At, and the most recently discovered Ts).

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The successive ionization energies of a certain element are I1 = 589.5 kJ/mol, I2 =1145 kJ/mol, I3= 4900 kJ/mol, I4 = 6500 kJ/mo
Gnom [1K]

Answer:

As

Explanation:

For any element to exhibit the pattern of ionization energy shown in the question, it must possess five electrons in its outermost shell. These five electrons are not lost at once. They are lost progressively until the valence shell becomes empty. The ionization energy increases steadily as more electrons are lost from the valence shell.

The only pentavalent element among the options in arsenic, hence the answer.

7 0
4 years ago
Read 2 more answers
In this equation, what should be the coefficients of the reactants and products? I2 + O2 → I4O9
denpristay [2]
4I₂+9O₂= 2I₄+2O₉
Reactants: 8 iodine, 18 oxygen
Products: 8 iodine, 18 oxygen
Balanced!!
3 0
3 years ago
How many electrons are in the second energy level of an atom of each element?
alexira [117]
Well they all have 8 electrons But it would be A I hope this is right
7 0
3 years ago
In an electrochemical cell, which direction to the electrons flow?
Jet001 [13]

Answer:

Electrons flow from anode to cathode (this is always the case). For an electrolytic cell however, this flow is not spontaneous but must be driven by an external power source. In an electrolytic cell, the anode has the "+" sign.

4 0
3 years ago
Calculate the amount of HCN that gives the lethal dose in a small laboratory room measuring 12.0 ft×15.0 ft×8.60ft.
Damm [24]

<u>Given:</u>

Dimensions of the room= 12 ft * 15 ft * 8.60 ft

<u>To determine:</u>

The amount of HCN that gives the lethal dose in the room with the given dimensions

<u>Explanation:</u>

As per the World Health Organization, the lethal dose of HCN is around 300 ppm

300 ppm = 300 mg of HCN/ kg of inhaled air

Volume of air = volume of room = 12 * 15 *8.6 = 1548 ft³

Now,  1 ft³ = 28316.8 cm³

Therefore, the calculated volume of air corresponds to:

1548 * 28316.8 = 4.383 * 10⁷ cm3

Density of air (at room temperature 25 C) = 0.00118 g/cm3

Thus mass of air corresponding to the calculated volume is

Mass = Density * volume = 0.00118 g/cm3 * 4.383 * 10⁷ cm3

= 5.172*10⁴ g = 51.72 kg

Lethal amount of HCN corresponding to 51.72 kg of air would be.

= 51.72 kg air* 300 mg of HCN/1 kg air = 15516 mg

Ans: Lethal dose of HCN = 15.5 g

5 0
3 years ago
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