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kupik [55]
3 years ago
9

If I mix 5 gallons of p% boric acid with 5 gallons of water, what is the concentration of the mixture?

Mathematics
1 answer:
Trava [24]3 years ago
4 0

Answer: The concentration of the mixture is 0.5 p % .

Step-by-step explanation:

Given: 5 gallons of p% boric acid is mixed with 5 gallons of water.

Amount of boric acid = p% of 5 gallons

=\dfrac{p}{100}\times5\text{ gallons}= 0.05p\text{ gallons}

Total solution : 5 +5 = 10 gallons

then, the concentration of the mixture = \dfrac{\text{Amount of boric acid in solution}}{\text{Total solution}}\times100

=\dfrac{0.05p}{10}\times100\\\\=0.5p

Hence, the concentration of the mixture is 0.5 p % .

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The average household income for a recent year was $30,000. five years earlier the average household income was $24,500. assume
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Using hypothesis test, we conclude that there is evidence to believe that the average household income has increased.

According to the question,

The average household income for a recent year (x₁⁻) = $30,000

The average household income for a recent year (x₂⁻) = $24,500

sample sizes n₁ = n₂ = 34

standard deviation of both samples were $24,500. Thus, s₁ = s₂ = $5928.

Null hypothesis:  There is no evidence to believe that the average household income has increased.

H₀ : μ₁ ≤ μ₂

Alternative hypothesis:  There is evidence to believe that the average household income has increased.

H₁: μ₁ > μ₂  

To check hypothesis we have the formula

Standard error=  \sqrt{\frac{s_{1} ^{2} }{n_{1} } + \frac{s^{2} _{2} }{n_{2} }  }

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Formula for test statistic = [(x₁⁻ -  x₂⁻) - (μ₁ - μ₂)]/standard error

= [(30000 -  24500) - 0]/1437.7512

= 3.8254

The critical value of z at 5% level of significance is 1.6449.

Here, the calculated value is greater than the critical value so we reject H₀.

Hence using hypothesis test, we conclude that there is evidence to believe that the average household income has increased.

Learn more about hypothesis test here

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