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Reika [66]
4 years ago
7

Find the product mentally.

Mathematics
2 answers:
yaroslaw [1]4 years ago
8 0
(ab+3)(ab−3)

=(ab+3)(ab+−3)

=(ab)(ab)+(ab)(−3)+(3)(ab)+(3)(−3)

=a^2b^2−3ab+3ab−9

=a^2b^2−9

WITCHER [35]4 years ago
4 0

Answer:

Option (c) is correct.

\left(ab\:+\:3\right)\left(ab\:-\:3\right)=a^2b^2-9

Step-by-step explanation:

Given : \left(ab\:+\:3\right)\left(ab\:-\:3\right)

We have to find the product of \left(ab\:+\:3\right)\left(ab\:-\:3\right)

Consider the given expression \left(ab\:+\:3\right)\left(ab\:-\:3\right)

Apply algebraic identity, \left(a+b\right)\left(a-b\right)=a^2-b^2

We have,

a = ab and b = 3

=\left(ab\right)^2-3^2

Simplify, we have,

=a^2b^2-9

Thus, \left(ab\:+\:3\right)\left(ab\:-\:3\right)=a^2b^2-9

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Joey built a model sailboat that is similar to his real sailboat. The triangular sail on
lord [1]

Answer:

31.25

Step-by-step explanation:

25/12=2.083333

15 x 2.0833333=31.24999999995

round up to get 31.25

3 0
3 years ago
Factorize a² +3ab - 5ab - 15b².
olga nikolaevna [1]

Answer:

a^2+3\,a\,b-5\,a\,b-15\,b^2=(a-5\,b)\,(a+3\,b)

Step-by-step explanation:

Work via factoring by groups:

!) re arrange the terms as follows:

a^2-5ab+3ab-15b^2

then extract the common factor for the first two terms (a), and separately the common factors for the last two terms (3 b):

a^2-5ab+3ab-15b^2\\a\,(a-5\,b)+3\,b\,(a-5\,b)

Now notice that the binomial factor (a-5 b) is in both expressions, so extract it:

a\,(a-5\,b)+3\,b\,(a-5\,b)\\(a-5\,b)\,(a+3\,b)

which is the final factorization.

5 0
3 years ago
Read 2 more answers
Fill in the table using this function rule y=10x+1
Mice21 [21]
Well you have no table for me to fill in but I can help you :)

Say that on the left side of your chart your x values are 1,2, and 3. 
just plug in those x values for x in the equation y=10x+1

so....
x        y
-----------
1      y=10(1)+1 = y = 11
------------
2       y = 10(2)+1 = y = 21
-------------
3       y = 10(3)+1 = y = 31

plz give me points :)
7 0
3 years ago
The sum of two numbers is equal to 70. Which of the following functions can be use to find the product of the two numbers if one
Temka [501]
Let x=number 1 let y=number2
there sum is equal to 70
then

number1+number2=70

substituting

x+y=70

y=70-x
let there product will be p
p=xy
substituting
p=x(70-x)
which is choice c

4 0
4 years ago
Does anyone know why x is normally used for an unknown number?
jeka94

Then you are able to substitute in X and it can have a infinite number of values catered to the question.

7 0
3 years ago
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