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Reika [66]
4 years ago
7

Find the product mentally.

Mathematics
2 answers:
yaroslaw [1]4 years ago
8 0
(ab+3)(ab−3)

=(ab+3)(ab+−3)

=(ab)(ab)+(ab)(−3)+(3)(ab)+(3)(−3)

=a^2b^2−3ab+3ab−9

=a^2b^2−9

WITCHER [35]4 years ago
4 0

Answer:

Option (c) is correct.

\left(ab\:+\:3\right)\left(ab\:-\:3\right)=a^2b^2-9

Step-by-step explanation:

Given : \left(ab\:+\:3\right)\left(ab\:-\:3\right)

We have to find the product of \left(ab\:+\:3\right)\left(ab\:-\:3\right)

Consider the given expression \left(ab\:+\:3\right)\left(ab\:-\:3\right)

Apply algebraic identity, \left(a+b\right)\left(a-b\right)=a^2-b^2

We have,

a = ab and b = 3

=\left(ab\right)^2-3^2

Simplify, we have,

=a^2b^2-9

Thus, \left(ab\:+\:3\right)\left(ab\:-\:3\right)=a^2b^2-9

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Please helpppp I need a answer asap
FinnZ [79.3K]

Answer:

280cm^2

Step-by-step explanation:

I am only looking for the shaded region which is 20 and 14 and 20*14=280

so my final answer will be 280cm^2

4 0
3 years ago
The sum of a number and its reciprocal is 13/6. find the number
iris [78.8K]
Suppose the number is x, its reciprocal is 1/x
x+1/x=13/6
(x^2+1)/x=13/6
6(x^2+1)=13x
6x^2-13x+6=0
(3x-2)(2x-3)=0
x=2/3 or x=3/2
6 0
3 years ago
This table shows values represented by an exponential function.
krok68 [10]

Answer:

C. 12

Step-by-step explanation:

Average rate of change = \frac{f(b) - f(a)}{b - a}

Where,

a = 1, f(a) = 3

b = 3, f(b) = 27

Average rate of change = \frac{27 - 3}{3 - 1}

Average rate of change = \frac{24}{2} = 12

Average rate of change for the interval from x = 1 to x = 3 is 12

4 0
3 years ago
I need help am i correct
nirvana33 [79]
13 x 5 = 65

4 x 7 = 28 

28 + 65 = 93

Your error is in you said 13 x 65 is 75
6 0
4 years ago
Read 2 more answers
Write the quadratic equation in general form. (x - 3)^ 2 = 0
algol [13]
The answer is:  x² – 6x + 9 = 0  .
_____________________________________________________
Explanation:
________________________________________________________

Given:  (x – 3)² = 0 ;  write as: general form:  "ax² + bx + c = 0";  a ≠ 0 .
<span>
Note:  </span>(x – 3)² = (x – 3)(x – 3) = x² – 3x – 3x + 9 = x² – 6x + 9 ;
___________________________________________________
Rewrite: (x – 3)²  =  0 ;  →
           as:   x² – 6x + 9 = 0  ; which is our answer.
____________________________________________
→   x² – 6x + 9 = 0  ; is in "general form", or "standard equation format"; that is: " ax² + bx + c = 0 ";  (a ≠ 0) ;
             → in which: 
   a =  1 (implied coefficient, since anything multiplied by "1" is that same                                                                                                                    value);
   b = -6; 
   c =  9
_______________________________________________________
5 0
3 years ago
Read 2 more answers
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