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Fofino [41]
3 years ago
5

Carlos worked at a farmers market on 4 summer weekends.He worked 5 hours on Saturday and 4 hours on Sunday.How many hours did Ca

rlos work in all a the farmers market?Explain how you know your answer is reasonable.
Mathematics
2 answers:
nevsk [136]3 years ago
3 0
Carlos worked a total of 36 hours at the farmers market.

I know my answer is reasonable because:
1. Multiply 5 by 4
2. Multiply 4 by 4
3.Add both of the products to get your answer
Arlecino [84]3 years ago
3 0
4x5=20
4x4=16
20+16=36
I multiplied 4x5 and 4x4 because he worked for. 4. Summer. Weekends. And 4 and 5. Hours each and then added to. Find. The total and. Got. 36 as my answer
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Answer:

The dimensions of the garden that minimize the cost is 9.018 feet(length) and 13.528 feet(width)

Step-by-step explanation:

Let the length of garden be x

Let the breadth of garden be y

Area of Rectangular garden = Length \times Breadth = xy

We are given that the area of the garden is 122 square feet

So, xy=122 ---A

A landscape architect wished to enclose a rectangular garden on one side by a brick wall costing $20/ft

So, cost of brick along length x = 20 x

On the other three sides by a metal fence costing $10/ft.

So, Other three side s = x+2y

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So, Total cost = 20x+10(x+2y)=20x+10x+20y=30x+20y

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Total cost = 30x+20(\frac{122}{x})

Total cost = \frac{2440}{x}+30x

Now take the derivative to minimize the cost

f(x)=\frac{2440}{x}+30x

f'(x)=-\frac{2440}{x^2}+30

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0=-\frac{2440}{x^2}+30

\frac{2440}{x^2}=30

\sqrt{\frac{2440}{30}}=x

9.018 =x

Now check whether it is minimum or not

take second derivative

f'(x)=-\frac{2440}{x^2}+30

f''(x)=-(-2)\frac{2440}{x^3}

Substitute the value of x

f''(x)=-(-2)\frac{2440}{(9.018)^3}

f''(x)=6.6540

Since it is positive ,So the x is minimum

Now find y

Substitute the value of x in A

(9.018)y=122

y=\frac{122}{9.018}

y=13.528

Hence the dimensions of the garden that minimize the cost is 9.018 feet(length) and 13.528 feet(width)

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