Answer:
A. 0
General Formulas and Concepts:
<u>Pre-Algebra
</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I
</u>
<u>Pre-Calculus
</u>
<u>Calculus
</u>
- Derivatives
- Derivative Notation
- Derivative of csc(x) =
![\frac{d}{dx} [csc(x)] = -csc(x)cot(x)](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bcsc%28x%29%5D%20%3D%20-csc%28x%29cot%28x%29)
Step-by-step explanation:
<u>Step 1: Define</u>
<u />![\frac{d}{dx} [csc(x)]\\x = \frac{3 \pi}{2}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bcsc%28x%29%5D%5C%5Cx%20%3D%20%5Cfrac%7B3%20%5Cpi%7D%7B2%7D)
<u />
<u />
<u>Step 2: Differentiate</u>
- Differentiate:
<u>Step 3: Evaluate</u>
- Substitute in <em>x</em>:
- Evaluate:
5x - 14y = 22 ⇒ 5x - 14y = 22
-6x + 7y = 3 ⇒ <u>12x - 14y = -6</u>
<u>-7x</u> = <u>28</u>
-7 -7
x = -4
5x - 14y = 22
5(-4) - 14y = 22
-20 - 14y = 22
<u>+ 20 + 20</u>
<u>-14y</u> = <u>42</u>
-14 -14
y = -3
(x, y) = (-4, -3)
Answer:
Volume of the frustum = ⅓πh(4R² - r²)
Step-by-step explanation:
We are to determine the volume of the frustum.
Find attached the diagram obtained from the given information.
Let height of small cone = h
height of the large cone = H
The height of a small cone is a quarter of the height of the large cone:
h = ¼×H
H = 4h
Volume of the frustum = volume of the large cone - volume of small cone
volume of the large cone = ⅓πR²H
= ⅓πR²(4h) = 4/3 ×π×R²h
volume of small cone = ⅓πr²h
Volume of the frustum = 4/3 ×π×R²h - ⅓πr²h
Volume of the frustum = ⅓(4π×R²h - πr²h)
Volume of the frustum = ⅓πh(4R² - r²)
First get n's by them selves
-6 = 10n -4n (remember to always change sign when crossing the equals sign.
-6 = 6n ( subtract and take sign of the larger) ( then divide both sides by 6 to solve for n)
-1 = n
hope this helps
Answer:
i don't now
Step-by-step explanation:
Sorry I couldn't help you
