Ask question

Ask question

All categories

3 years ago

13

An 85% chance that a flight on Broadway Airlines is on time out of a total of 600 flights. How many are expected to arrive on ti

me.

1 answer:

Slav-nsk [51]3 years ago

8 0

600 * 0.85 (the way to work out 85% of something) = 510 flights on time

You might be interested in

In 1996 the population of Capital City was 7,255,731 and the population of Sprung City was

Hoochie [10]

The answer is (1) because 7,300,000-3,900,000 is 3,400,000

6 0

3 years ago

Read 2 more answers

I need help someone pls help me I been on this for to long

11Alexandr11 [23.1K]

Step-by-step explanation:

the explanation is above

Take key note of the dots bcz some are coloured and some aren't

6 0

3 years ago

Read 2 more answers

Two-thirds of the books on the shelf are paperbacks. The library

IgorC [24]

Answer:

There are 80 paperbacks on the shelf

Step-by-step explanation:

Multiply 2/3 by 120

So that would be:

2/3 x 120/1

(2 x 120)/(3x1)=240/3=80

6 0

2 years ago

LM is the midsegment of ABC is AC is 28 centimeters long , how long is LM?

mamaluj [8]

Answer:

LM = 14

Step-by-step explanation:

LM = AC/2

LM = 28/2

<u>LM = 14</u>

Hope this helps!

4 0

3 years ago

Given circle and circle with radii of 6cm and 4cm respectively.

noname [10]

Solution :

Given that :

The radius of circle A = 6 cm

The radius of circle C = 4 cm

In circle A

$\angle EAF = \theta = 140^\circ$

The length of arc EF = $2 \pi r \times \frac{\theta}{360^\circ}$

$=2 \times 3.14 \times 6 \times \frac{140^\circ}{360^\circ}$

= 14.653 cm

In circle C

$\angle GCH = \theta = 140^\circ$

The length of arc GH = $2 \pi r \times \frac{\theta}{360^\circ}$

$=2 \times 3.14 \times 4 \times \frac{140^\circ}{360^\circ}$

= 9.769 cm

Therefore,

The length of EF is 14.653 cm

The length of GH is 9.769 cm

The length of EF is 1.5 times the length of GH

i.e. 14.653 = 1.5 x 9.769

14.653 = 14.653

Hence proved.

6 0

3 years ago